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@ManishaRana1195
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@super30admin
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Strengths:

  1. The approach of using two binary searches is correct and efficient.
  2. The code is well-commented and easy to follow.
  3. The time and space complexity are optimal.

Areas for Improvement:

  1. The use of Integer.MAX_VALUE and Integer.MIN_VALUE is not necessary and can be misleading. Instead, you should return -1 if the target is not found, similar to the reference solution.
  2. The boundary checks for the first and last occurrences are not handled correctly. For example, when mid == 0 or mid == nums.length - 1, you should check if the adjacent elements are different to confirm the first or last occurrence.
  3. The initial checks for len == 0 and len == 1 are good, but the logic for len == 1 can be simplified.
  4. The variable names startIndex and endIndex are clear, but initializing them to extreme values is not ideal.

Suggested Improvements:

  1. Replace the use of Integer.MAX_VALUE and Integer.MIN_VALUE with -1 and handle the cases where the target is not found.
  2. Add proper boundary checks for the first and last occurrences, similar to the reference solution.
  3. Simplify the logic for edge cases like len == 1.

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2 participants