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BFS-2-1 completed#633

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BFS-2-1 completed#633
prattiiksha wants to merge 1 commit into
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Oranges getting rotten (rotten_orange_994.cpp)

Strengths:

  1. Clean and well-structured BFS implementation
  2. Good variable naming and code organization
  3. Correctly handles edge cases (empty grid, no fresh oranges)
  4. Proper use of queue for level-order traversal
  5. TC and SC comments show awareness of complexity analysis

Areas for Improvement:

  1. The early return optimization (checking fresh == 0 inside the BFS loop and returning immediately) could make the solution slightly faster in cases where all oranges rot before the queue is empty
  2. Consider adding a check after decrementing fresh to return immediately when it reaches 0, similar to the reference solution

Minor Note:
The solution is functionally correct and produces the right answer. The time-1 return is correct because time is incremented after processing each "minute" of oranges.

VERDICT: PASS


Importance of Employee (employee_imp_690.cpp)

Strengths:

  • Correct BFS approach to traverse the employee hierarchy
  • Good use of unordered_map for O(1) employee lookup
  • Clear variable naming (total, q for queue)
  • Proper handling of employees with no subordinates

Areas for Improvement:

  • The space complexity comment "SC: O(1)" is incorrect - the solution uses O(N) space for the hash map and queue
  • The check if(employees.size()==0) return 0; is unnecessary since the while loop handles this case naturally
  • Consider adding comments explaining the algorithm for better maintainability
  • The continue statement in the else block is redundant; the loop will proceed anyway

Minor optimization: The else block with continue can be simplified since the loop naturally continues after processing subordinates.

VERDICT: PASS

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