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Resolves #477
Essentially, completely uniformizable spaces are those spaces whose Kolmogorov quotient is realcompact.

Perhaps some theorems about realcompact spaces could be replaced by those involving completely uniformizable spaces

@yhx-12243
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Later I (or you of others) may propose a property namely “Extent less than every measurable cardinal”, as a complete helper for this. (I've preparing for the property of “Extent < 𝖈”, as mentioned in #1398 (comment))

@Moniker1998
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@yhx-12243 we could, but we won't be introducing any spaces of size larger than the first measurable cardinal, as far as I know

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Yes, just like P164 (Cardinality less than every measurable cardinal).

@Moniker1998
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P164 has its use, and this is the reason why the extent property is not needed

@prabau
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prabau commented Sep 1, 2025

It seems "Dieudonné complete" is a better primary name for this. (see Engelking 8.5.13 and Encyclopedia of General Topology pp. 205, 254, 262.)

See Engelking for more topological characterizations for this, in particular items (2) and (3).

@Moniker1998 Moniker1998 marked this pull request as draft September 1, 2025 23:03
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prabau commented Sep 2, 2025

Are you sure about "topologically complete" as an alias?
Which source uses that for Dieudonne complete?

If I recall, that term may have been used for various other things as well, maybe for completely metrizable or Cech-complete. It's rather confusing.

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Moniker1998 commented Sep 2, 2025

@prabau wikipedia, which cites Kelley

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@prabau I don't think another alias is bad, I did the same thing with ultranormal property. There shouldn't be confusion as those are just aliases.
Thanks for the references by the way. I am trying to go through Engelking's exercise and will add it once I verify it's true

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prabau commented Sep 2, 2025

Adding another alias is fine if it has been used somewhere for the same concept. In that case, we should put a note at the bottom mentioning the alternate name with reference.

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T382 could be replaced by $R_0$ + normal + submetacompact $\implies$ Dieudonne complete, perhaps
T386 we can replace with pseudocompact + Dieudonne complete $\implies$ compact

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yhx-12243 commented Sep 2, 2025

T382 could be replaced by R₀ + normal + submetacompact ⟹ Dieudonne complete

Wrong. See notes in https://www.ams.org/journals/proc/1973-040-02/S0002-9939-1973-0322812-9/S0002-9939-1973-0322812-9.pdf, if measurable cardinality exists.

So I suggest add an extra weaker but correct theorem: R₁ + paracompact ⟹ Dieudonne complete (it can solve the unknown traits in pi-base now, though)

T386 we can replace with pseudocompact + Dieudonne complete ⟹ compact

This is right.

@Moniker1998
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@prabau I've noticed there's no spaces which are $T_4$ and subparacompact, but not paracompact. I'm guessing those are equivalent?

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@prabau I've noticed there's no spaces which are T 4 and subparacompact, but not paracompact. I'm guessing those are equivalent?

#742 is the counterexample. See https://scispace.com/pdf/on-subparacompact-spaces-2o1ji8yodk.pdf.

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Ah okay. Another reason to add this eventually

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yhx-12243 commented Sep 2, 2025

How do you think to add “R₁ + paracompact ⟹ Dieudonne complete” ?

@Moniker1998
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There is an exercise in Engelking referencing three papers, I assume one of them contains a somewhat easier proof of this

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Oddly enough, I haven't found easy proof online, but I did find converse for GO-spaces

@Moniker1998 Moniker1998 marked this pull request as ready for review September 2, 2025 09:36
@Moniker1998 Moniker1998 changed the title Completely uniformizable Dieudonne complete Sep 2, 2025
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@prabau please review

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@prabau want to review this one?

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Add completely uniformizable property

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