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fix(api): make public CRON job paths transactional with pg_cron #33
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🧩 Analysis chain
🌐 Web query:
pg_cron unschedule function behavior when job name not found💡 Result:
When you call the pg_cron function cron.unschedule(job_name text) and the specified job name cannot be found for the current user, the function raises a PostgreSQL error [1][2]. Specifically, the implementation of cron_unschedule_named in the pg_cron source code performs a lookup in the cron.job table filtering by both the job name and the current user's identity [2]. If no tuple is found matching these criteria, the function executes an ereport with the error message: "could not find valid entry for job '[job_name]'" [2]. This behavior means that: - You will receive an error rather than a boolean false return value [1][2]. - If you are logged in as a different user than the one who created the job, the function will fail with this "not found" error even if the job name exists in the table, because it cannot locate a matching entry for your current user [3][1]. - To avoid this error, you must ensure the job name exists and is owned by the current database role executing the command [1][2]. Alternatively, you can use the cron.unschedule(jobid bigint) function if you have the job ID, as it may have different permission handling characteristics [3][1].
Citations:
cron.unschedule(jobid)can unschedule jobs of another user butcron.unschedule(jobname)cannot citusdata/pg_cron#320Make
unregister_pg_cron_connidempotent for missing pg_cron jobscron.unschedule($1)with the job name raises a PostgreSQL error (e.g., “could not find valid entry for job …”) when no matching entry exists for the current user, sounregister_pg_cron_conn(crates/common/src/db/jobs.rs, lines 315-329) can returnErr(sqlx::Error)instead of succeeding. Adjust to either pre-checkcron.jobfor that name/ownership (and only then callcron.unschedule), or catch/translate the specific “not found” error toOk(())(or usecron.unschedule(jobid bigint)if you can supply the job id).🤖 Prompt for AI Agents