Week5Lab1

files_for_lab/solutions.sql

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+-- Exercise 1
+--### Query 1
+
+--Get the `id` values of the first 5 clients from `district_id` with a value equals to 1.
+
+SELECT client_id FROM client
+WHERE district_id=1
+LIMIT 5;
+
+--### Query 2
+--In the `client` table, get an `id` value of the last client where the `district_id` equals to 72.
+
+SELECT client_id FROM client
+WHERE district_id=72
+ORDER BY client_id DESC
+LIMIT 1;
+
+--### Query 3
+--Get the 3 lowest amounts in the `loan` table.
+
+SELECT amount
+FROM loan
+ORDER BY amount ASC
+LIMIT 3;
+
+--## Query 4
+--## What are the possible values for `status`, ordered alphabetically in ascending order in the `loan` table?
+
+SELECT DISTINCT status
+FROM loan
+ORDER BY status ASC;
+
+--## Query 5
+SELECT account_id, amount
+FROM loan
+ORDER BY account_id ASC
+LIMIT 5;
+
+--## Query 6
+-- What is the loan `amount` of the lowest 5 `account_id`s in the `loan` table? Show the `account_id` and the corresponding `amount`
+
+SELECT account_id, amount
+FROM loan
+ORDER BY account_id ASC
+LIMIT 5;
+
+--##Query 7
+SELECT account_id
+FROM loan
+WHERE duration = 60
+  AND amount = (
+      SELECT MIN(amount)
+      FROM loan
+      WHERE duration = 60
+  );
+
+--##Query 8
+SELECT DISTINCT k_symbol
+FROM `order`
+ORDER BY k_symbol ASC;
+
+--##Query 9
+SELECT order_id
+FROM `order`
+WHERE account_id = 34
+ORDER BY order_id ASC;
+
+--##Query 10
+SELECT DISTINCT account_id
+FROM `order`
+WHERE order_id BETWEEN 29540 AND 29560
+ORDER BY account_id ASC;
+
+--##Query 11
+SELECT DISTINCT amount
+FROM `order`
+WHERE account_to = 30067122;
+
+--##QUERY 12
+SELECT trans_id, date, type, amount
+FROM trans
+WHERE account_id = 793
+ORDER BY date DESC, trans_id DESC
+LIMIT 10;
+
+--##Query 13
+SELECT district_id, COUNT(*) AS number_of_clients
+FROM client
+WHERE district_id < 10
+GROUP BY district_id
+ORDER BY district_id ASC;
+
+--##Query 14
+SELECT type, COUNT(*) AS number_of_cards
+FROM card
+GROUP BY type
+ORDER BY number_of_cards DESC;
+
+--##Query 15
+SELECT account_id, SUM(amount) AS total_loan_amount
+FROM loan
+GROUP BY account_id
+ORDER BY total_loan_amount DESC
+LIMIT 10;
+
+--##QUERY 16
+SELECT date, COUNT(*) AS number_of_loans
+FROM loan
+WHERE date < 930907
+GROUP BY date
+ORDER BY date DESC;
+
+--##QUERY 17
+SELECT date, duration, COUNT(*) AS number_of_loans
+FROM loan
+WHERE date BETWEEN 971201 AND 971231
+GROUP BY date, duration
+ORDER BY date ASC, duration ASC;
+
+--##QUERY 18
+SELECT account_id, type, SUM(amount) AS total_amount
+FROM trans
+WHERE account_id = 396
+GROUP BY account_id, type
+ORDER BY type ASC;