Solved Lab

index.js

@@ -1,7 +1,59 @@
 // Iteration 1: Names and Input
+/*1.1 Create a variable hacker1 with the driver's name.
+1.2 Print "The driver's name is XXXX".
+1.3 Create a variable hacker2 with the navigator's name.
+1.4 Print "The navigator's name is YYYY".*/
+
+const hacker1 = "Joan"
+const hacker2 = "Lorena"
+
+console.log(`The driver's name is ${hacker1}`)
+console.log(`The navigator's name is ${hacker2}`)
 
 
 // Iteration 2: Conditionals
+/*2.1. Depending on which name is longer, print:
+- The driver has the longest name, it has XX characters. or
+- It seems that the navigator has the longest name, it has XX characters. or
+- Wow, you both have equally long names, XX characters!.*/
+
+if ( hacker1.length > hacker2.length){
+    console.log(`The driver has the longest name, it has ${hacker1.length} characters`)
+}
+else if( hacker1.length < hacker2.length){
+    console.log(`It seems that the navigator has the longest name, it has ${hacker2.length} characters`)
+}
+else{
+    console.log( `Wow, you both have equally long names, ${hacker1.length} characters!`)
+}
 
 
 // Iteration 3: Loops
+
+/*3.1 Print the characters of the driver's name, separated by space, and in capital letters, i.e., "J O H N".
+3.2 Print all the characters of the navigator's name in reverse order, i.e., "nhoJ".
+3.3 Depending on the lexicographic order of the strings, print
+The driver's name goes first.
+Yo, the navigator goes first, definitely.
+What?! You both have the same name?*/
+
+//3.1
+for (let i=0; i<hacker1.length; i++){
+   console.log(hacker1[i].toUpperCase())
+}
+//3.2
+for (let j=hacker2.length; j>-1; j--){
+    console.log(hacker2[j])
+}
+//3.3
+const nameOrder= hacker1.localeCompare(hacker2);
+
+    if (nameOrder===-1){
+console.log(`The driver's name goes first.`)
+    }
+    else if (nameOrder===0){
+console.log(`Yo, the navigator goes first, definitely.`)      
+    }
+    else {
+console.log(`What?! You both have the same name?`)     
+    }