Week 2 HW - Henna

[xhenna92]

No description provided.

[mikekavouras]

This code is technically correct, however, it can be optimized into a single loop:

    for (int i = 1; i<25; i++) {
            NSString * decoded2 = [self decode:string2 offset:i];
            if ([string1 isEqualToString:decoded2]) {
                return YES;
            }
    }

    return NO;

The difference is wost case 25 iterations vs. worst case 600+ iterations.