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# Problem

Find out all LCS of《ABACABAC》and《CABCBAAB》.

# Solution

## Example

解LCS所設計的遞迴公式：

```c
c[i, j] = 0 if i = 0 or j = 0
= c[i-1, j-1] + 1 if i, j > 0 and x_𝑖 = y_𝑖
= max(c[i, j-1], c[i-1, j]) if i, j > 0 and x_i ≠ y_j
```

![LCS Length Table](https://i.imgur.com/VeUrq5b.jpg)

- ABAAB
- ABCAB
- ABCAA
- ABCBA