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Groove Rivercrossing

This project contains a solution for the missionary and cannibal problem. It was implemented by using Groove.

Missionary and cannibal problem

Three missionaries and three cannibals are standing next to a river. They want to get all to the other side, but they always need someone that can row. All three missionaries are able to row. There is also one cannibal that is able to row. Cannibals are actually pretty friendly people, but if there are more cannibals than missionaries on one side their hunger overcomes their rationality.

Solution

The following table describes a possible solution with the applied grammar-rules.
πŸ§™β€β™‚οΈ = Missionary, πŸ§Ÿβ€β™‚οΈ = Cannibal, πŸš£β€β™‚οΈ = Cannibal that can row

πŸ”„ πŸ‘ˆ β›΅ πŸ‘‰ 🧾
0 πŸ§™β€πŸ§™β€πŸ§™β€πŸ§Ÿβ€πŸ§Ÿβ€πŸš£β€ load
4 πŸ§™β€β™‚οΈπŸ§™β€πŸ§Ÿβ€πŸš£β€β™‚οΈ πŸ§™β€πŸ§Ÿβ€β™‚οΈ unload-two
8 πŸ§™β€β™‚οΈπŸ§™β€πŸ§Ÿβ€πŸš£β€β™‚οΈ πŸ§™β€πŸ§Ÿβ€ load
14 πŸ§™β€β™‚οΈπŸ§™β€πŸ§Ÿβ€πŸš£β€β™‚οΈ πŸ§™β€β™‚οΈ πŸ§Ÿβ€ unload-one
21 πŸ§™β€β™‚οΈπŸ§™β€β™‚οΈπŸ§™β€πŸ§Ÿβ€πŸš£β€β™‚οΈ πŸ§Ÿβ€ load
30 πŸ§™β€β™‚οΈπŸ§™β€β™‚οΈπŸ§™β€ πŸ§Ÿβ€πŸš£β€ πŸ§Ÿβ€ unload-two
33 πŸ§™β€β™‚οΈπŸ§™β€β™‚οΈπŸ§™β€ πŸ§Ÿβ€β™‚οΈπŸ§Ÿβ€β™‚οΈπŸš£ load
35 πŸ§™β€β™‚οΈπŸ§™β€β™‚οΈπŸ§™β€ πŸš£β€β™‚οΈ πŸ§Ÿβ€πŸ§Ÿβ€ unload-one
36 πŸ§™β€β™‚οΈπŸ§™β€β™‚οΈπŸ§™β€πŸš£β€β™‚οΈ load
38 πŸ§™β€πŸš£β€β™‚οΈ πŸ§™β€πŸ§™β€ πŸ§Ÿβ€πŸ§Ÿβ€ unload-two
41 πŸ§™β€πŸš£β€β™‚οΈ πŸ§™β€πŸ§™β€πŸ§Ÿβ€πŸ§Ÿβ€ load
45 πŸ§™β€πŸš£β€β™‚οΈ πŸ§™β€β™‚οΈπŸ§Ÿβ€β™‚οΈ πŸ§™β€πŸ§Ÿβ€β™‚οΈ unload-two
46 πŸ§™β€πŸ§™β€πŸ§Ÿβ€β™‚οΈπŸš£β€ πŸ§™β€πŸ§Ÿβ€β™‚οΈ load
49 πŸ§™β€πŸ§Ÿβ€β™‚ πŸ§™β€β™‚οΈπŸš£ πŸ§™β€πŸ§Ÿβ€β™‚οΈ unload-two
54 πŸ§™β€πŸ§Ÿβ€β™‚ πŸ§™β€β™‚οΈπŸ§™β€πŸ§Ÿβ€β™‚οΈπŸš£β€ load
62 πŸ§™β€πŸ§Ÿβ€β™‚ πŸ§™β€πŸ§Ÿβ€β™‚ πŸ§™β€β™‚οΈπŸš£β€ unload-two
67 πŸ§™β€πŸ§™β€πŸ§Ÿβ€πŸ§Ÿβ€ πŸ§™β€β™‚οΈπŸš£β€ load
72 πŸ§Ÿβ€πŸ§Ÿβ€ πŸ§™β€β™‚οΈπŸ§™β€β™‚οΈ πŸ§™β€β™‚οΈπŸš£β€ unload-two
74 πŸ§Ÿβ€β™‚οΈπŸ§Ÿβ€β™‚οΈ πŸ§™β€β™‚οΈπŸ§™β€β™‚οΈπŸ§™β€πŸš£β€β™‚οΈ load
78 πŸ§Ÿβ€πŸ§Ÿβ€ πŸš£β€ πŸ§™β€πŸ§™β€πŸ§™β€ unload-one
80 πŸ§Ÿβ€πŸ§Ÿβ€πŸš£β€ πŸ§™β€πŸ§™β€πŸ§™β€ load
81 πŸ§Ÿβ€ πŸ§Ÿβ€πŸš£β€ πŸ§™β€πŸ§™β€πŸ§™β€ unload-two
83 πŸ§Ÿβ€ πŸ§™β€πŸ§™β€πŸ§™β€πŸ§Ÿβ€πŸš£β€ load
84 πŸ§Ÿβ€ πŸ§™β€β™‚οΈ πŸ§™β€πŸ§™β€πŸ§Ÿβ€β™‚οΈπŸš£β€ unload-one
90 πŸ§™β€πŸ§Ÿβ€β™‚οΈ πŸ§™β€πŸ§™β€πŸ§Ÿβ€β™‚οΈπŸš£β€ load
92 πŸ§™β€πŸ§Ÿβ€β™‚οΈ πŸ§™β€πŸ§™β€πŸ§Ÿβ€β™‚οΈπŸš£β€ unload-two
96 πŸ§™β€β™‚οΈπŸ§™β€β™‚οΈπŸ§™β€πŸ§Ÿβ€πŸ§Ÿβ€πŸš£β€β™‚οΈ final

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Solution to Three missionaries and three cannibals problem

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