The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
0 ≤ x, y < 231.
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
class Solution {
public:
int hammingDistance(int x, int y) {
int count=0;
bitset<32>binary1(x);bitset<32>binary2(y);
for(int i=0;i<32;i++)if(binary1[i]!=binary2[i])count++;
return count;
}
};