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53 changes: 53 additions & 0 deletions data_structures/fiboSum.cpp
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// https://www.spoj.com/problems/FIBOSUM/
// sum=fibo(m+2)-fibo(n+1), here answer can be negative, so be careful.
// https://codegeeksblog.wordpress.com/2013/06/02/spoj-fibosum/

// To find nth fibonacci number in log(n) time please see below concepts.
// See this link https://cp-algorithms.com/algebra/binary-exp.html
// https://cp-algorithms.com/algebra/fibonacci-numbers.html
// Video https://www.youtube.com/watch?v=EEb6JP3NXBI
#include <bits/stdc++.h>
using namespace std;
long long MAX = 1000000007;
void multiply(long long F[2][2], long long M[2][2])
{
long long w = ((F[0][0] * M[0][0]) % MAX + (F[0][1] * M[1][0]) % MAX) % MAX;
long long x = ((F[0][0] * M[0][1]) % MAX + (F[0][1] * M[1][1]) % MAX) % MAX;
long long y = ((F[1][0] * M[0][0]) % MAX + (F[1][1] * M[1][0]) % MAX) % MAX;
long long z = ((F[1][0] * M[0][1]) % MAX + (F[1][1] * M[1][1]) % MAX) % MAX;
F[0][0] = w;
F[0][1] = x;
F[1][0] = y;
F[1][1] = z;
}
void power(long long F[2][2], long long n)
{
if (n == 0 || n == 1)
return;
long long M[2][2] = {{1, 1}, {1, 0}};
power(F, n / 2);
multiply(F, F);
if (n & 1)
multiply(F, M);
}
long long fibo(long long n)
{
long long F[2][2] = {{1, 1}, {1, 0}};
if (n == 0)
return 0;
power(F, n - 1);
return F[0][0];
}
int main()
{
long long t, n, m;
cin >> t;
while (t--)
{
cin >> m >> n;
// Here added MAX because to remove negative sign.
cout << (fibo(n + 2) - fibo((m - 1) + 2) + MAX) % MAX << endl;
}
return 0;
}