Space - Hala #18
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Space - Hala #18
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CheezItMan
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Sep 15, 2020
CheezItMan
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CheezItMan
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Not bad, you have all the solutions working. You can do things a bit more efficiently using hashes a bit more. This is something to practice a bit as you prepare for interviews.
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| # Time Complexity: O(n2) | ||
| # Space Complexity: O(n) | ||
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| def grouped_anagrams(strings) |
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👍 This works, but you can do better by sorting the words and using the sorted letters as keys for all the anagrams
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| numHash.keys.each do |num| | ||
| if returnList.length < k | ||
| returnList<< num |
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Suggested change
| returnList<< num | |
| returnList<< num |
| numHash = {} | ||
| returnList = [] | ||
| list.each do |num| | ||
| if numHash.keys.include?(num) |
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Can be simplified
Suggested change
| if numHash.keys.include?(num) | |
| unless numHash[num].nil? |
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| # Time Complexity: O(n2) | ||
| # Space Complexity: O(n) | ||
| def top_k_frequent_elements(list, k) |
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Your solution has 3 loops which each run n times. It also sorts the array. So the method is O(n log n) in time complexity.
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Hash Table Practice
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Comprehension Questions