Leaves - Samantha #43
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CheezItMan
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Sep 19, 2019
CheezItMan
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CheezItMan
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Nice work, both methods do the job. Do see my note on the time complexity of delete_at.
| i = 0 | ||
| while i < list.length | ||
| if list[i] == list[i+1] | ||
| list.delete_at(i) |
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delete_at shifts all subsequent elements left one index each. This is an O(n) method. Since it's nested inside a loop running n times, this means the method is an O(n2) algorithm.
| # Space Complexity: ? | ||
| # Time Complexity: O(nm) - depends on the length of strings = n and length of string[0] = m | ||
| # Space Complexity: O(m) - is reacreting a result total | ||
| def longest_prefix(strings) |
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