diff --git a/02_activities/assignments/DC_Cohort/Assignment1.md b/02_activities/assignments/DC_Cohort/Assignment1.md index f78778f5b..ab2d7c5ba 100644 --- a/02_activities/assignments/DC_Cohort/Assignment1.md +++ b/02_activities/assignments/DC_Cohort/Assignment1.md @@ -205,5 +205,9 @@ Consider, for example, concepts of fariness, inequality, social structures, marg ``` -Your thoughts... + +I dont' really encounter many databases on the day-to-day basis beyond my own neuroscience research. In general there could be that demographic information could help understand socioeconomic structures in clinical settings when looking at different groups of patients, which can be used to see if certain racial groups are disadvantaged or not receiving the right amount of medical care. I could also expect to see this census data, when looking a job disparities between various groups and how resources are allocated to serve different communities based on their specific needs. How we code in demographic information such as sex, gender, age, race, nationality and immigration status can impact how resources are distributed to different communities. If we do not have enough comprehensive distinctions between certain groups, then it may be difficult to get the targeted needs met for certain groups that require more assistance. + + + ``` diff --git a/02_activities/assignments/DC_Cohort/ERD Logical Map.png b/02_activities/assignments/DC_Cohort/ERD Logical Map.png new file mode 100644 index 000000000..5bfa33846 Binary files /dev/null and b/02_activities/assignments/DC_Cohort/ERD Logical Map.png differ diff --git a/02_activities/assignments/DC_Cohort/assignment1.sql b/02_activities/assignments/DC_Cohort/assignment1.sql index c992e3205..cd919be55 100644 --- a/02_activities/assignments/DC_Cohort/assignment1.sql +++ b/02_activities/assignments/DC_Cohort/assignment1.sql @@ -4,29 +4,38 @@ --SELECT /* 1. Write a query that returns everything in the customer table. */ +SELECT * FROM customer; - - -/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, -sorted by customer_last_name, then customer_first_ name. */ - +/* 2. Write a query that displays all of the columns and 10 rows from the customer table, +sorted by customer_last_name, then customer_first_name. */ +SELECT * +FROM customer +ORDER BY customer_last_name, customer_first_name +LIMIT 10; --WHERE /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */ - - - -/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), -filtered by customer IDs between 8 and 10 (inclusive) using either: - 1. two conditions using AND - 2. one condition using BETWEEN +SELECT * +FROM customer_purchases +WHERE product_id IN (4, 9); + +/*2. Write a query that returns all customer purchases and a new calculated column 'price' +(quantity * cost_to_customer_per_qty), filtered by customer IDs between 8 and 10 (inclusive) using either: + 1. two conditions using AND + 2. one condition using BETWEEN */ --- option 1 - - --- option 2 +-- option 1 (AND) +SELECT *, + quantity * cost_to_customer_per_qty AS price +FROM customer_purchases +WHERE customer_id >= 8 AND customer_id <= 10; +-- option 2 (BETWEEN) +SELECT *, + quantity * cost_to_customer_per_qty AS price +FROM customer_purchases +WHERE customer_id BETWEEN 8 AND 10; --CASE @@ -34,20 +43,40 @@ filtered by customer IDs between 8 and 10 (inclusive) using either: Using the product table, write a query that outputs the product_id and product_name columns and add a column called prod_qty_type_condensed that displays the word “unit” if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */ - - +SELECT product_id, + product_name, + CASE WHEN product_qty_type = 'unit' THEN 'unit' + ELSE 'bulk' + END AS prod_qty_type_condensed +FROM product; /* 2. We want to flag all of the different types of pepper products that are sold at the market. -add a column to the previous query called pepper_flag that outputs a 1 if the product_name +Add a column to the previous query called pepper_flag that outputs a 1 if the product_name contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */ - +SELECT product_id, + product_name, + CASE WHEN product_qty_type = 'unit' THEN 'unit' + ELSE 'bulk' + END AS prod_qty_type_condensed, + CASE WHEN lower(product_name) LIKE '%pepper%' THEN 1 + ELSE 0 + END AS pepper_flag +FROM product; --JOIN /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */ - - +SELECT v.vendor_name, + v.vendor_type, + v.vendor_owner_first_name, + v.vendor_owner_last_name, + vba.market_date, + vba.booth_number +FROM vendor AS v +INNER JOIN vendor_booth_assignments AS vba + ON v.vendor_id = vba.vendor_id +ORDER BY v.vendor_name, vba.market_date; /* SECTION 3 */ @@ -55,15 +84,25 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t -- AGGREGATE /* 1. Write a query that determines how many times each vendor has rented a booth at the farmer’s market by counting the vendor booth assignments per vendor_id. */ - - +SELECT vendor_id, + COUNT(*) AS booth_rentals +FROM vendor_booth_assignments +GROUP BY vendor_id; /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list of customers for them to give stickers to, sorted by last name, then first name. HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */ - +SELECT c.customer_first_name, + c.customer_last_name, + SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent +FROM customer AS c +INNER JOIN customer_purchases AS cp + ON c.customer_id = cp.customer_id +GROUP BY c.customer_id, c.customer_first_name, c.customer_last_name +HAVING total_spent > 2000 +ORDER BY c.customer_last_name, c.customer_first_name; --Temp Table @@ -77,20 +116,40 @@ When inserting the new vendor, you need to appropriately align the columns to be -> To insert the new row use VALUES, specifying the value you want for each column: VALUES(col1,col2,col3,col4,col5) */ +DROP TABLE IF EXISTS temp.new_vendor; +CREATE TEMP TABLE temp.new_vendor AS SELECT * FROM vendor; - +INSERT INTO temp.new_vendor + (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name) +VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal'); -- Date /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table. HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month and year are! */ - - +SELECT customer_id, + strftime('%m', market_date) AS month, + strftime('%Y', market_date) AS year +FROM customer_purchases; /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. Remember that money spent is quantity*cost_to_customer_per_qty. HINTS: you will need to AGGREGATE, GROUP BY, and filter... but remember, STRFTIME returns a STRING for your WHERE statement!! */ - +SELECT + c.customer_first_name, + c.customer_last_name, + SUM(cp.quantity * cp.cost_to_customer_per_qty) AS april_2022_spent +FROM ( + SELECT customer_id, + strftime('%Y-%m', market_date) AS year_month + FROM customer_purchases +) AS dated_purchases +INNER JOIN customer AS c ON dated_purchases.customer_id = c.customer_id +INNER JOIN customer_purchases AS cp ON c.customer_id = cp.customer_id + AND strftime('%Y-%m', cp.market_date) = dated_purchases.year_month +WHERE dated_purchases.year_month = '2022-04' +GROUP BY c.customer_id, c.customer_first_name, c.customer_last_name +ORDER BY april_2022_spent DESC;