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zigzag-conversion.rb
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60 lines (40 loc) · 1.24 KB
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# The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
# P A H N
# A P L S I I G
# Y I R
# And then read line by line: "PAHNAPLSIIGYIR"
# Write the code that will take a string and make this conversion given a number of rows:
# string convert(string s, int numRows);
# Example 1:
# Input: s = "PAYPALISHIRING", numRows = 3
# Output: "PAHNAPLSIIGYIR"
# Example 2:
# Input: s = "PAYPALISHIRING", numRows = 4
# Output: "PINALSIGYAHRPI"
# Explanation:
# P I N
# A L S I G
# Y A H R
# P I
# Example 3:
# Input: s = "A", numRows = 1
# Output: "A"
# Constraints:
# 1 <= s.length <= 1000
# s consists of English letters (lower-case and upper-case), ',' and '.'.
# 1 <= numRows <= 1000
def convert(s, num_rows)
return s if num_rows <= 1
rows = Array.new(num_rows) {[]}
going_down = true
current_row = 0
next_row_modifier = 1
s.each_char do |c|
rows[current_row] << c
going_down = false if current_row == num_rows - 1
going_down = true if current_row == 0
next_row_modifier = going_down ? 1 : -1
current_row += next_row_modifier
end
rows.flatten.join
end