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112.path-sum.cpp
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70 lines (70 loc) · 1.73 KB
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/*
* @lc app=leetcode id=112 lang=cpp
*
* [112] Path Sum
*
* https://leetcode.com/problems/path-sum/description/
*
* algorithms
* Easy (38.44%)
* Total Accepted: 344.6K
* Total Submissions: 894.5K
* Testcase Example: '[5,4,8,11,null,13,4,7,2,null,null,null,1]\n22'
*
* Given a binary tree and a sum, determine if the tree has a root-to-leaf path
* such that adding up all the values along the path equals the given sum.
*
* Note: A leaf is a node with no children.
*
* Example:
*
* Given the below binary tree and sum = 22,
*
*
* 5
* / \
* 4 8
* / / \
* 11 13 4
* / \ \
* 7 2 1
*
*
* return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
*
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool hasPathSum(TreeNode* root, int sum) {
vector<TreeNode *> layer;
if (root == NULL)
return false;
layer.push_back(root);
while (layer.empty() == false) {
vector<TreeNode *> next;
for (auto node : layer) {
if (node->val == sum && node->left == NULL && node->right == NULL)
return true;
if (node->left) {
node->left->val += node->val;
next.push_back(node->left);
}
if (node->right) {
node->right->val += node->val;
next.push_back(node->right);
}
}
layer.swap(next);
}
return false;
}
};