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majority element-II.cpp
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77 lines (74 loc) · 1.71 KB
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//Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times.
#include<bits/stdc++.h>
using namespace std;
vector<int> majorityElement(vector<int>& nums) {
int n=nums.size();
vector<int> ans;
if(n==0)return ans;
if(n==1)return nums;
set<int>s;
int val1=nums[0];
int count1=1;
int val2=nums[0];
int count2=0;
for(int i=1;i<n;i++){
if(nums[i]==val1){
count1++;
}else if(nums[i]==val2){
count2++;
}else if(nums[i]!=val1&&nums[i]!=val2)
{
if(count1==0){
val1=nums[i];
count1=1;
}else if(count2==0){
val2=nums[i];
count2=1;
}else{
count1--;
count2--;
}
}
}
int c1=0;
for(int i=0;i<n;i++){
if(nums[i]==val1){
c1++;
}
}
int c2=0;
for(int i=0;i<n;i++){
if(nums[i]==val2){
c2++;
}
}
// vector<int> ans;
if(val1==val2){
if(c1>n/3){
ans.push_back(val1);
return ans;
}
}
else{
if(c1>n/3){
ans.push_back(val1);
}
if(c2>n/3){
ans.push_back(val2);
}
}
return ans;
}
int main(){
int n;
cin>>n;
vector<int> arr(n);
for(int i=0;i<n;i++){
cin>>arr[i];
}
vector<int> ans=majorityElement(arr);
for(int i=0;i<ans.size();i++){
cout<< ans[i]<<" ";
}
return 0;
}