Design a max stack that supports push, pop, top, peekMax and popMax.
push(x) -- Push element x onto stack. pop() -- Remove the element on top of the stack and return it. top() -- Get the element on the top. peekMax() -- Retrieve the maximum element in the stack. popMax() -- Retrieve the maximum element in the stack, and remove it. If you find more than one maximum elements, only remove the top-most one.
Example 1:
MaxStack stack = new MaxStack(); stack.push(5); stack.push(1); stack.push(5); stack.top(); -> 5 stack.popMax(); -> 5 stack.top(); -> 1 stack.peekMax(); -> 5 stack.pop(); -> 1 stack.top(); -> 5
Note:
- -1e7 <= x <= 1e7
- Number of operations won't exceed 10000.
- The last four operations won't be called when stack is empty.
stack
class MaxStack {
public:
/** initialize your data structure here. */
MaxStack() {}
void push(int x) {
if (s2.empty() || s2.top() <= x) s2.push(x);
s1.push(x);
}
int pop() {
if (!s2.empty() && s2.top() == s1.top()) s2.pop();
int t = s1.top(); s1.pop();
return t;
}
int top() {
return s1.top();
}
int peekMax() {
return s2.top();
}
int popMax() {
int mx = s2.top();
stack<int> t;
while (s1.top() != s2.top()) {
t.push(s1.top()); s1.pop();
}
s1.pop(); s2.pop();
while (!t.empty()) {
push(t.top()); t.pop();
}
return mx;
}
private:
stack<int> s1, s2;
};Running time : O(n)