Hey :)
Any way of making the circle full without modifying the library?
Maybe passing a -1 or something can indicate a full circle which would then use 2*Pi for the calculation (or whatever it is)..
Otherwise, thanks so much for the work! If you'd prefer I make some changes for this and submit a PR, I'll happily do that!
Cheers
Hey :)
Any way of making the circle full without modifying the library?
Maybe passing a
-1or something can indicate a full circle which would then use 2*Pi for the calculation (or whatever it is)..Otherwise, thanks so much for the work! If you'd prefer I make some changes for this and submit a PR, I'll happily do that!
Cheers