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Q: In a college of 500 students, 285 took Mathematics, 195 took Statistics, 115 took English, 70 took Mathematics and Statistics, 45 took Mathematics and English, 50 took Statistics and English, and 10 took all three courses. What is the total number of students who took none of these three subjects?
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A: **60** (Using the principle of inclusion-exclusion)[^1].
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8.**Short Answer**
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Q: (No question text)
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A: **37**[^1].
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9.**Short Answer**
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Q: (No question text)
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A: **-9**[^1].
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10.**Short Answer**
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Q: (No question text)
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A: **-1**[^1].
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11.**Short Answer**
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Q: R1 \ R2
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A: **6**[^1].
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12.**Short Answer**
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Q: R2
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A: **4**[^1].
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13.**Short Answer**
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Q: (No question text)
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A: **14**[^1].
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14.**Short Answer**
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Q: (No question text)
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A: **3**[^1].
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## Question 1
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**Question:**
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Consider the polynomials \$ p(x) = x^5 - 3x^4 + 100x - 1 \$ and \$ q(x) = x^5 + x + 5 \$. Which of the following statements are correct?
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-\$ p(x) + q(x) \to \infty \$ as \$ x \to -\infty \$
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-\$ p(x) - q(x) \to -\infty \$ as \$ x \to \infty \$
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-\$ -5p(x) \to -\infty \$ as \$ x \to -\infty \$
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-\$ \frac{1}{2}q(x) \to \infty \$ as \$ x \to -\infty \$
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**Step-by-Step Solution:**
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1.**Leading Terms Analysis:**
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- Both \$ p(x) \$ and \$ q(x) \$ have the leading term \$ x^5 \$.
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- For large \$ |x| \$, the highest degree term dominates.
A bird is flying along the straight line $2y - 6x = 6$. After some time an aeroplane also follows the straight line path with a slope of 2 and passes through the point (4,8). Let $(\alpha, \beta)$ be the point where the bird and aeroplane can collide. Then find the value of $\alpha + \beta$.
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**Step-by-Step Solution:**
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1.**Bird's Path:**
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The equation $2y - 6x = 6$ can be rewritten as:
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$2y = 6x + 6 \implies y = 3x + 3$
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So, the bird's path is $y = 3x + 3$.
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2.**Aeroplane's Path:**
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Slope = 2, passes through (4,8):
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Equation: $y - 8 = 2(x - 4)$
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$y = 2x - 8 + 8 = 2x$
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3.**Point of Collision:**
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Set the $y$ values equal:
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$3x + 3 = 2x$
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$x = -3$
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Substitute $x = -3$ into either equation (use bird's path):
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$y = 3(-3) + 3 = -9 + 3 = -6$
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So, $(\alpha, \beta) = (-3, -6)$.
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$\alpha + \beta = -3 + (-6) = -9$
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{{< border type="question" >}}
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The polynomial $p(x) = a(x-4)(x-6)(x-8)(x-10)$ passes through the vertex of the quadratic function $q(x) = -(x-7)^2 - 9$. Calculate the value of $a$.
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**Step-by-Step Solution:**
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1.**Vertex of $q(x)$:**
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The vertex form is $q(x) = -(x-7)^2 - 9$.
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So, vertex is at $(7, -9)$.
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2.**$p(x)$ passes through (7, -9):**
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Substitute $x = 7, p(7) = -9$:
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$p(7) = a(7-4)(7-6)(7-8)(7-10) = a(3)(1)(-1)(-3)$
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$= a \times 3 \times 1 \times -1 \times -3 = a \times 9$
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So, $a \times 9 = -9$
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$a = -1$
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{{< border type="question" >}}
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Consider a set $S = \{a \mid a \in \mathbb{N}, a \leq 14\}$. Let $R_1$ and $R_2$ be relations on $S \times S$ defined as $R_1 = \{(x, y) \mid x, y \in S, y = 2x\}$ and $R_2 = \{(x, y) \mid x, y \in S, y = x^2\}$. Find the cardinality of the given sets in the subquestions.
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**Subquestion 1:** Find the cardinality of $R_1 \setminus R_2$.
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**Step-by-Step Solution:**
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1.**Elements of $S$:**
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$S = \{1, 2, 3, ..., 14\}$
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2.**$R_1$:**
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$y = 2x$ and $y \leq 14$
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For $x = 1$ to $7$, $y = 2, 4, 6, 8, 10, 12, 14$
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So, $R_1 = \{(1,2), (2,4), (3,6), (4,8), (5,10), (6,12), (7,14)\}$
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