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Gives root of quadratic equation.

Author: parz1val37

codes_in_Aug2025/Solving_quadratic.py

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+import math
+print("General form of quadratic is: ax^2 + bx + c, where (a!=0).")
+a = int(input("Enter the value for a: "))
+if a == 0:
+    print("a can't be equals to zero.")
+else:
+    b = int(input("Enter the value for b: "))
+    c = int(input("Enter the value for c: "))
+    if c == 0:
+        print(f"The quadratic is: {a}x^2 + {b}x")
+    else:
+        print(f"The quadratic is: {a}x^2 + {b}x + {c}")
+
+    d = b**2 - 4*a*c
+    
+    if d<0:
+        d = d*(-1)
+        x = str(2*a)
+        print("This quadratic have complex roots.")
+        root1 = (f"{(-1*b)} + i{round(math.sqrt(d), 2)}")
+        root2 = (f"{(-1*b)} - i{round(math.sqrt(d), 2)}") 
+        print(f"The roots of given quadratic are \'{root1}/{x}\' and \'{root2}/{x}\'.")
+    
+    elif d == 0:
+        print("This quadratic have equal roots.")
+        print(f"Which is \'{(-b/(2*a))}\'.")
+    
+    else:
+        print("This quadratic have two real and distinct roots.")
+        root1 = (-b + round(math.sqrt(d), 2))/(2*a)
+        root2 = (-b - round(math.sqrt(d), 2))/(2*a)
+        print(f"Which are \'{root1}\' and \'{root2}\'.")