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Mixin without plugins #1

@cadorn

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@cadorn

I need an export.mixin() that does not include the plugin functionality as it conflicts with function names that are already on my object.

Maybe add two exports:

exports.mixinObservable
exports.mixinPlugins

The exports.mixin can stay and always include all functionality although that may cause problems if more features are added in future that conflict with existing object functions.

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