From 72bccf6ee82ea8f8c204fb5054f241532ff3de3c Mon Sep 17 00:00:00 2001
From: pfatheddin <156558883+pfatheddin@users.noreply.github.com>
Date: Sun, 24 Mar 2024 19:36:43 -0400
Subject: [PATCH] Update LinearApproximations3.tex

https://ximera.osu.edu/mooculus/linearApproximation/exercises/exerciseList/linearApproximation/exercises/LinearApproximations3

I added the interval they need to check this at. It is important to give the interval since on written homework they ask them to give the interval even if it is positive always.
---
 linearApproximation/exercises/LinearApproximations3.tex | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/linearApproximation/exercises/LinearApproximations3.tex b/linearApproximation/exercises/LinearApproximations3.tex
index b261b2e0b..467c8213b 100644
--- a/linearApproximation/exercises/LinearApproximations3.tex
+++ b/linearApproximation/exercises/LinearApproximations3.tex
@@ -58,7 +58,7 @@
 \frac{4}{2.8} \approx \answer{4-2.8}.
 \]
 
-This approximation is an \wordChoice{\choice{overestimate}\choice[correct]{underestimate}} because $f(x)$ is concave \wordChoice{\choice[correct]{up}\choice{down}} and the graph of $L$ lies \wordChoice{\choice{above}\choice[correct]{below}} the graph of $f$ near $a=2$.
+This approximation is an \wordChoice{\choice{overestimate}\choice[correct]{underestimate}} because $f(x)$ is concave \wordChoice{\choice[correct]{up}\choice{down}} on the interval $(2, \answer{2.8}). Thus, the graph of $L$ lies \wordChoice{\choice{above}\choice[correct]{below}} the graph of $f$ near $a=2$.
 
 The percent error,PE, in an approximation is given by
 \[
@@ -163,4 +163,4 @@
 \end{multipleChoice}
 
 \end{exercise}
-\end{document}
\ No newline at end of file
+\end{document}