From 4b683e6274ef839d0626ccc5025ddf32331c6f6e Mon Sep 17 00:00:00 2001
From: pfatheddin <156558883+pfatheddin@users.noreply.github.com>
Date: Sun, 24 Mar 2024 18:01:52 -0400
Subject: [PATCH] Update meanValueTheorem4.tex

https://ximera.osu.edu/mooculus/meanValueTheorem/exercises/exerciseList/meanValueTheorem/exercises/meanValueTheorem4

Took out the hint. They did so many average rate problems in past assignments and will probably know this formula.
---
 meanValueTheorem/exercises/meanValueTheorem4.tex | 6 ++----
 1 file changed, 2 insertions(+), 4 deletions(-)

diff --git a/meanValueTheorem/exercises/meanValueTheorem4.tex b/meanValueTheorem/exercises/meanValueTheorem4.tex
index e6b360d8f..a6aefd1ae 100644
--- a/meanValueTheorem/exercises/meanValueTheorem4.tex
+++ b/meanValueTheorem/exercises/meanValueTheorem4.tex
@@ -29,9 +29,7 @@
 \]
 \begin{exercise}
 Compute the average rate of change of the population during the time interval $[0,4]$.
-\begin{hint}
-Recall, the average rate of change of the population during the time interval $[0,4]$ is given by the expression $\frac{P\left(\answer{4}\right)-P\left(\answer{0}\right)}{4-0}$.
-\end{hint}
+
 The average rate of change of the population during the time interval $[0,4]$ is $\answer{20}$ million cells per week.
 \end{exercise}
 \begin{exercise}
@@ -39,4 +37,4 @@
 
 That means that at the time $t=c$ the \textbf{instantaneous rate of change} of the population is equal to the \textbf{average rate of change} of the population during the time interval $[0,4]$.
 \end{exercise}
-\end{document}
\ No newline at end of file
+\end{document}