@@ -315,3 +315,78 @@ implement this combined method.
315315
316316[^ haeser_scf]: M. Häser, R. Ahlrichs, _J. Comput. Chem._, ** 1989 ** , 10 , 104 & ndash;111 .
317317
318+ # ## Problem 4
319+
320+ The so- called spin- orbit coupling (SOC ) plays a crucial role in the transition
321+ between singlet and triplet states. All spin- related effects are ultimately
322+ derived from the relativistic Dirac equation. Since the derivation of SOC
323+ from the Dirac formalism is rather lengthy, we will not go into detail here.
324+ After applying several transformations, one arrives at the following
325+ additional term in the Hamiltonian:
326+ $$
327+ \frac{\hbar}{4m^2 c^2} \bm{\sigma} \cdot (\mathbf{\nabla}V) \times \mathbf{p}
328+ $$
329+
330+ Here, $ \bm{\sigma}$ denotes the vector of Pauli matrices, $V$ is
331+ the nuclear potential, $ \mathbf{p}$ is the momentum operator, and $m$ and $c$
332+ refer to the electron mass and the speed of light, respectively.
333+ The potential $ V$ is given by:
334+ $$
335+ \begin{align*}
336+ V(\mathbf{r}) &= \sum_n \frac{Z_n}{r_n}\\
337+ \mathbf{\nabla}V(\mathbf{r})
338+ & = \sum_n \frac{Z_n}{r_n^3}(\mathbf{r}-\mathbf{C}_n)
339+ \end{align*}
340+ $$
341+ with $ Z_n$ being the nuclear charge and $ \mathbf{C}_n$ the position of the
342+ $ n$ th nucleus. Substituting this into the SOC term leads to a
343+ more compact expression:
344+ $$
345+ \frac{\hbar}{4m^2c^2} \bm{\sigma} \cdot \sum_n \frac{Z_n}{r_n^3}(\mathbf{r}-\mathbf{C}_n) \times \mathbf{p} = \frac{\hbar}{4m^2c^2} \bm{\sigma} \cdot \sum_n \frac{Z_n}{r_n^3}\mathbf{l}_n
346+ $$
347+ where $ \mathbf{l}_n = (\mathbf{r}-\mathbf{C}_n) \times \mathbf{p}$
348+ is the angular momentum operator with respect to nucleus $ n$ .
349+ We can now separate the spin and spatial parts of the SOC operator:
350+ $$
351+ \begin{align*}
352+ \frac{\hbar}{4m^2c^2} \bm{\sigma} \cdot \sum_n \frac{Z_n}{r_n^3}\mathbf{l}_n = \bm{\sigma} \cdot \left( \frac{\hbar}{4m^2c^2} \sum_n \frac{Z_n}{r_n^3}\mathbf{l}_n\right)
353+ \end{align*}
354+ $$
355+
356+ Although SOC integrals can in principle be evaluated for arbitrary
357+ Gaussian orbitals, in this task we will restrict ourselves to the SOC
358+ matrix element between two identical p< sub> z< / sub> - type orbitals with the
359+ same exponent $ \alpha$. These orbitals are defined as:
360+ $$
361+ \begin{align*}
362+ \phi_{i,p_z}(\mathbf{r}) &= N z \exp\left(-\alpha \left( (x - \frac{d}{2})^2 + y^2 + z^2\right)\right) \\
363+ \phi_{j,p_z}(\mathbf{r}) &= N z \exp\left(-\alpha \left( (x + \frac{d}{2})^2 + y^2 + z^2\right)\right)\;\mathrm{.}
364+ \end{align*}
365+ $$
366+ Here, the $ x$ - axis is chosen as the bond axis, and $ d$ is the distance between
367+ the centres of the two orbitals. $ N$ is the normalization factor, which will be
368+ ignored in the derivation since it does not affect the structure of the SOC term.
369+
370+ ** Compute the spatial part of the SOC matrix element between the two
371+ p< sub> z< / sub> - orbitals:**
372+ $$
373+ \begin{align*}
374+ \frac{\hbar}{4m^2c^2} \sum_n Z_n \int \du^3 {\mathbf{r}}\ \phi_{i,p_z}^*(\mathbf{r})
375+ \begin{pmatrix}
376+ \hat{l}_{n,x} \\
377+ \hat{l}_{n,y} \\
378+ \hat{l}_{n,z}
379+ \end{pmatrix}
380+ \frac{1}{r_n^3} \phi_{j,p_z}(\mathbf{r})
381+ \end{align*}
382+ $$
383+
384+ * Hint:
385+ Since the angular momentum operator is a vector, the result of this integral
386+ will also be a vector with three components. Therefore, you will need to
387+ evaluate three integrals, one for each spatial component of the angular momentum.
388+ Use the relevant expressions and techniques from the lecture to simplify
389+ the integrals. You are encouraged to use SymPy to assist with the
390+ symbolic computation of the integrals where appropriate.*
391+
392+
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