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Hope to add a method for calculating the hypotenuse with three parameters : double double.Hypot(double, double, double) #1449

@QuarkSoftware

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@QuarkSoftware

Hope to add a method for calculating the hypotenuse with three parameters : double double.Hypot(double, double, double), Equivalent to Math.Sqrt(x * x + y * y + z * z), Simplified double.Hypot(double.Hypot(x, y), z)

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