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LeetCode-347
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66 lines (62 loc) · 1.73 KB
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/*
找出数组nums中出现频率最高的k个元素
哈希表+大顶堆
*/
class Solution {
public:
map<int, int> m;
vector<int> topKFrequent(vector<int>& nums, int k) {
int i, cur;
vector<int> queue, v;
for(i = 0; i < nums.size(); ++i)
{
m[nums[i]]++;
}
sort(nums.begin(), nums.end());
nums.erase(unique(nums.begin(), nums.end()), nums.end());
for(i = 0; i < nums.size(); ++i)
{
queue.push_back(nums[i]);
}
cur = (nums.size()-2) / 2;
while(cur >= 0)
{
siftdown(queue, cur);
cur--;
}
for (i = 0; i < k; ++i)
{
v.push_back(queue[0]);
queue[0] = queue[queue.size() - 1];
queue.pop_back();
siftdown(queue, 0);
}
return v;
}
void siftdown(vector<int>& queue, int pos)
{
int temp;
if ((2 * pos + 2) < queue.size() && (2 * pos + 1) < queue.size())
{
temp = max(max(m[queue[2 * pos + 2]], m[queue[2 * pos + 1]]), m[queue[pos]]);
if (temp == m[queue[2 * pos + 2]])
{
swap(queue[pos], queue[2 * pos + 2]);
siftdown(queue, 2 * pos + 2);
}
else if (temp == m[queue[2 * pos + 1]])
{
swap(queue[pos], queue[2 * pos + 1]);
siftdown(queue, 2 * pos + 1);
}
}
else if ((2 * pos + 1) < queue.size())
{
if (m[queue[pos]] < m[queue[2 * pos + 1]])
{
swap(queue[pos], queue[2 * pos + 1]);
siftdown(queue, 2 * pos + 1);
}
}
}
};