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Solution51.java
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58 lines (47 loc) · 1.51 KB
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class Solution {
public int reversePairs(int[] nums) {
if (nums == null || nums.length < 2) {
return 0;
}
int[] tmp = new int[nums.length];
return reversePairs(nums, 0, nums.length - 1, tmp);
}
private int reversePairs(int[] nums, int left, int right, int[] tmp) {
if (left == right) {
return 0;
}
int mid = left + (right - left) / 2;
int leftPairs = reversePairs(nums, left, mid, tmp);
int rightPairs = reversePairs(nums, mid + 1, right, tmp);
int count = mergetAndCount(nums, left, mid, right, tmp);
return leftPairs + rightPairs + count;
}
private int mergetAndCount(int[] nums, int left, int mid, int right, int[] tmp) {
for (int i = left; i <= right; i++) {
tmp[i] = nums[i];
}
int i = left;
int j = mid + 1;
int count = 0;
for (int k = left; k <= right; k++) {
if (i == mid + 1) {
nums[k] = tmp[j];
j++;
} else if (j == right + 1) {
nums[k] = tmp[i];
i++;
} else if (tmp[i] <= tmp[j]) {
nums[k] = tmp[i];
i++;
} else {
nums[k] = tmp[j];
j++;
count += mid - i + 1;
}
}
return count;
}
}
/**
* https://leetcode-cn.com/problems/shu-zu-zhong-de-ni-xu-dui-lcof/solution/shu-zu-zhong-de-ni-xu-dui-by-leetcode-solution/
*/