From eddfeb404687c010aaaef211295a05e9d14da391 Mon Sep 17 00:00:00 2001
From: Mohamed Omari <omari@MacBookPro.box>
Date: Mon, 27 Apr 2026 19:07:14 +0200
Subject: [PATCH] SQL lab done

---
 solutions.sql | 130 ++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 130 insertions(+)
 create mode 100644 solutions.sql

diff --git a/solutions.sql b/solutions.sql
new file mode 100644
index 0000000..4709444
--- /dev/null
+++ b/solutions.sql
@@ -0,0 +1,130 @@
+--- Get the id values of the first 5 clients from district_id with a value equals to 1.
+
+SELECT district_id 
+FROM client
+WHERE district_id = 1
+ORDER BY client_id ASC
+LIMIT 5;
+
+--- In the client table, get an id value of the last client where the district_id equals to 72.
+
+SELECT client_id
+FROM client
+WHERE district_id = 72
+ORDER BY client_id DESC
+LIMIT 1;
+
+--- Get the 3 lowest amounts in the loan table.
+
+SELECT amount
+FROM loan
+ORDER BY amount ASC
+LIMIT 3;
+
+--- What are the possible values for status, ordered alphabetically in ascending order in the loan table?
+SELECT DISTINCT status
+FROM loan 
+ORDER BY  status ASC;
+
+--- What is the loan_id of the highest payment received in the loan table?
+
+SELECT loan_id
+FROM loan
+ORDER BY  payments DESC
+LIMIT 1;
+
+--- What is the loan amount of the lowest 5 account_ids in the loan table? Show the account_id and the corresponding amount
+
+SELECT account_id, amount
+FROM loan 
+ORDER by account_id ASC
+LIMIT 5;
+
+--- What are the account_ids with the lowest loan amount that have a loan duration of 60 in the loan table?
+
+SELECT account_id
+FROM loan 
+WHERE duration = 60
+ORDER BY amount ASC
+LIMIT 5;
+
+--- What are the unique values of k_symbol in the order table?
+
+SELECT DISTINCT k_symbol
+FROM 'order'
+WHERE k_symbol IS NOT NULL
+	AND TRIM(k_symbol) != ''
+ORDER by k_symbol ASC;
+
+--- In the order table, what are the order_ids of the client with the account_id 34?
+
+SELECT order_id 
+FROM 'order'
+WHERE account_id = 34;
+
+--- In the order table, which account_ids were responsible for orders between order_id 29540 and order_id 29560 (inclusive)?
+
+SELECT DISTINCT account_id
+FROM 'order'
+WHERE  order_id BETWEEN 29540 AND 29560;
+
+--- In the order table, what are the individual amounts that were sent to (account_to) id 30067122?
+SELECT amount
+FROM 'order'
+WHERE account_to = 30067122;
+
+--- In the trans table, show the trans_id, date, type and amount of the 10 first transactions from account_id 793 in chronological order, from newest to oldest.
+SELECT trans_id, date, type, amount
+FROM trans
+WHERE account_id = 793
+ORDER BY  date DESC
+LIMIT 10;
+
+--- In the client table, of all districts with a district_id lower than 10, how many clients are from each district_id? Show the results sorted by the district_id in ascending order.
+
+SELECT count(client_id)
+FROM client
+WHERE district_id < 10
+GROUP BY district_id
+ORDER BY district_id ASC;
+
+--- In the card table, how many cards exist for each type? Rank the result starting with the most frequent type.
+
+SELECT type, count(*) AS num_cards
+FROM card
+GROUP BY type
+ORDER BY count(type) DESC;
+
+--- Using the loan table, print the top 10 account_ids based on the sum of all of their loan amounts.
+
+SELECT account_id, sum(amount) AS sum_amount
+FROM loan
+GROUP BY account_id
+ORDER BY sum(amount) DESC
+LIMIT 10;
+
+--- In the loan table, retrieve the number of loans issued for each day, before (excl) 930907, ordered by date in descending order.
+
+SELECT date, COUNT(*) AS num_loans
+FROM loan
+WHERE date < 930907
+GROUP BY date 
+ORDER BY date  DESC;
+
+--- In the loan table, for each day in December 1997, count the number of loans issued for each unique loan duration, 
+--- ordered by date and duration, both in ascending order. You can ignore days without any loans in your output.
+
+SELECT date, duration, COUNT(*) AS num_loans
+FROM loan
+WHERE date BETWEEN 971201 AND 971231
+GROUP BY date, duration
+ORDER BY date ASC, duration ASC;
+
+--- In the trans table, for account_id 396, sum the amount of transactions for each type (VYDAJ = Outgoing, PRIJEM = Incoming). 
+--- Your output should have the account_id, the type and the sum of amount, named as total_amount. Sort alphabetically by type.
+
+SELECT account_id, type, SUM(amount) AS total_amount
+FROM trans
+WHERE account_id = 396
+GROUP BY account_id, type
+ORDER BY type ASC;
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