This kata is from check py.checkio.org
You are given an array with positive numbers and a number N. You should find the N-th power of the element in the array with the index N. If N is outside of the array, then return -1. Don't forget that the first element has the index 0.
Let's look at a few examples:
array = [1, 2, 3, 4]andN = 2, then the result is3^2 == 9;array = [1, 2, 3]andN = 3, but N is outside of the array, so the result is-1.
def index(array, n):
passdef index(array, n):
return array[n] ** n if n < len(array) else -1