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Investigate precision of invIncompleteBeta a b x for very small x #44

@Shimuuar

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@Shimuuar

Function could return answers which are orders of magnitude off. It could be due to the fact that we revert to bisection which is linear instead of cubic Halley.

>>> (\a b -> incompleteBeta a b . invIncompleteBeta a b) 90 90 1e-200
9.866213992257607e-197

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