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489-RobotRoomCleaner.go
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125 lines (111 loc) · 4.67 KB
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package main
// 489. Robot Room Cleaner
// You are controlling a robot that is located somewhere in a room.
// The room is modeled as an m x n binary grid where 0 represents a wall and 1 represents an empty slot.
// The robot starts at an unknown location in the room that is guaranteed to be empty,
// nd you do not have access to the grid, but you can move the robot using the given API Robot.
// You are tasked to use the robot to clean the entire room (i.e., clean every empty cell in the room).
// The robot with the four given APIs can move forward, turn left, or turn right. Each turn is 90 degrees.
// When the robot tries to move into a wall cell, its bumper sensor detects the obstacle, and it stays on the current cell.
// Design an algorithm to clean the entire room using the following APIs:
// interface Robot {
// // returns true if next cell is open and robot moves into the cell.
// // returns false if next cell is obstacle and robot stays on the current cell.
// boolean move();
// // Robot will stay on the same cell after calling turnLeft/turnRight.
// // Each turn will be 90 degrees.
// void turnLeft();
// void turnRight();
// // Clean the current cell.
// void clean();
// }
// Note that the initial direction of the robot will be facing up.
// You can assume all four edges of the grid are all surrounded by a wall.
// Custom testing:
// The input is only given to initialize the room and the robot's position internally.
// You must solve this problem "blindfolded".
// In other words, you must control the robot using only the four mentioned APIs without knowing the room layout and the initial robot's position.
// Example 1:
// <img src="https://assets.leetcode.com/uploads/2021/07/17/lc-grid.jpg" />
// Input: room = [[1,1,1,1,1,0,1,1],[1,1,1,1,1,0,1,1],[1,0,1,1,1,1,1,1],[0,0,0,1,0,0,0,0],[1,1,1,1,1,1,1,1]], row = 1, col = 3
// Output: Robot cleaned all rooms.
// Explanation: All grids in the room are marked by either 0 or 1.
// 0 means the cell is blocked, while 1 means the cell is accessible.
// The robot initially starts at the position of row=1, col=3.
// From the top left corner, its position is one row below and three columns right.
// Example 2:
// Input: room = [[1]], row = 0, col = 0
// Output: Robot cleaned all rooms.
// Constraints:
// m == room.length
// n == room[i].length
// 1 <= m <= 100
// 1 <= n <= 200
// room[i][j] is either 0 or 1.
// 0 <= row < m
// 0 <= col < n
// room[row][col] == 1
// All the empty cells can be visited from the starting position.
import "fmt"
/**
* // This is the robot's control interface.
* // You should not implement it, or speculate about its implementation
* type Robot struct {
* }
*
* // Returns true if the cell in front is open and robot moves into the cell.
* // Returns false if the cell in front is blocked and robot stays in the current cell.
* func (robot *Robot) Move() bool {}
*
* // Robot will stay in the same cell after calling TurnLeft/TurnRight.
* // Each turn will be 90 degrees.
* func (robot *Robot) TurnLeft() {}
* func (robot *Robot) TurnRight() {}
*
* // Clean the current cell.
* func (robot *Robot) Clean() {}
*/
// dfs
func cleanRoom(robot *Robot) {
dirs := [][]int{{-1,0}, {0,1}, {1,0}, {0,-1}}
visited := make(map[int]map[int]bool)
back := func() {
robot.TurnRight()
robot.TurnRight()
robot.Move();
robot.TurnRight()
robot.TurnRight()
}
var backtrack func(r,c,d int)
backtrack = func(r,c,d int){
if _,ok := visited[r]; !ok {
visited[r] = make(map[int]bool)
}
visited[r][c] = true
robot.Clean()
for i := 0; i < 4; i++ {
nd := (d+i) % 4
nr, nc := r + dirs[nd][0], c + dirs[nd][1]
if v,ok := visited[nr];(!ok||!v[nc]) && robot.Move() {
backtrack(nr,nc,nd)
back()
}
robot.TurnRight();
}
}
backtrack(0,0,0)
}
func main() {
// Example 1:
// <img src="https://assets.leetcode.com/uploads/2021/07/17/lc-grid.jpg" />
// Input: room = [[1,1,1,1,1,0,1,1],[1,1,1,1,1,0,1,1],[1,0,1,1,1,1,1,1],[0,0,0,1,0,0,0,0],[1,1,1,1,1,1,1,1]], row = 1, col = 3
// Output: Robot cleaned all rooms.
// Explanation: All grids in the room are marked by either 0 or 1.
// 0 means the cell is blocked, while 1 means the cell is accessible.
// The robot initially starts at the position of row=1, col=3.
// From the top left corner, its position is one row below and three columns right.
fmt.Println()
// Example 2:
// Input: room = [[1]], row = 0, col = 0
// Output: Robot cleaned all rooms.
}