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2006-CountNumberOfPairsWithAbsoluteDifferenceK.go
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90 lines (79 loc) · 2.28 KB
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package main
// 2006. Count Number of Pairs With Absolute Difference K
// Given an integer array nums and an integer k,
// return the number of pairs (i, j) where i < j such that |nums[i] - nums[j]| == k.
// The value of |x| is defined as:
// x if x >= 0.
// -x if x < 0.
// Example 1:
// Input: nums = [1,2,2,1], k = 1
// Output: 4
// Explanation: The pairs with an absolute difference of 1 are:
// - [1,2,2,1]
// - [1,2,2,1]
// - [1,2,2,1]
// - [1,2,2,1]
// Example 2:
// Input: nums = [1,3], k = 3
// Output: 0
// Explanation: There are no pairs with an absolute difference of 3.
// Example 3:
// Input: nums = [3,2,1,5,4], k = 2
// Output: 3
// Explanation: The pairs with an absolute difference of 2 are:
// - [3,2,1,5,4]
// - [3,2,1,5,4]
// - [3,2,1,5,4]
// Constraints:
// 1 <= nums.length <= 200
// 1 <= nums[i] <= 100
// 1 <= k <= 99
import "fmt"
func countKDifference(nums []int, k int) int {
res, n := 0, len(nums)
abs := func(x int) int { if x < 0 { return -x; }; return x; }
for i := 0; i < n ; i++ {
for j := i + 1; j < n ; j++ {
if abs(nums[i] - nums[j]) == k {
res++
}
}
}
return res
}
func countKDifference1(nums []int, k int) int {
mp := make(map[int]int)
res := 0
for _, v := range nums {
res += mp[v- k] + mp[v +k ]
mp[v]++
}
return res
}
func main() {
// Example 1:
// Input: nums = [1,2,2,1], k = 1
// Output: 4
// Explanation: The pairs with an absolute difference of 1 are:
// - [1,2,2,1]
// - [1,2,2,1]
// - [1,2,2,1]
// - [1,2,2,1]
fmt.Println(countKDifference([]int{1,2,2,1}, 1)) // 4
// Example 2:
// Input: nums = [1,3], k = 3
// Output: 0
// Explanation: There are no pairs with an absolute difference of 3.
fmt.Println(countKDifference([]int{1,3}, 3)) // 0
// Example 3:
// Input: nums = [3,2,1,5,4], k = 2
// Output: 3
// Explanation: The pairs with an absolute difference of 2 are:
// - [3,2,1,5,4]
// - [3,2,1,5,4]
// - [3,2,1,5,4]
fmt.Println(countKDifference([]int{3,2,1,5,4}, 2)) // 3
fmt.Println(countKDifference1([]int{1,2,2,1}, 1)) // 4
fmt.Println(countKDifference1([]int{1,3}, 3)) // 0
fmt.Println(countKDifference1([]int{3,2,1,5,4}, 2)) // 3
}