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144-BinaryTreePreorderTraversal.go
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84 lines (74 loc) · 1.72 KB
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package main
// 144. Binary Tree Preorder Traversal
// Given the root of a binary tree, return the preorder traversal of its nodes' values.
// Example 1:
// <img src="https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg"/>
// Input: root = [1,null,2,3]
// Output: [1,2,3]
// Example 2:
// Input: root = []
// Output: []
// Example 3:
// Input: root = [1]
// Output: [1]
// Constraints:
// The number of nodes in the tree is in the range [0, 100].
// -100 <= Node.val <= 100
import "fmt"
// Definition for a binary tree node.
type TreeNode struct {
Val int
Left *TreeNode
Right *TreeNode
}
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func preorderTraversal(root *TreeNode) []int {
var res []int
preorder(root, &res)
return res
}
// 递归
func preorder (root *TreeNode, output *[]int) {
if root != nil {
// 前序遍历
*output = append(*output, root.Val)
preorder(root.Left, output)
preorder(root.Right, output)
}
}
func main() {
// Example 1:
// <img src="https://assets.leetcode.com/uploads/2020/09/15/inorder_1.jpg"/>
// Input: root = [1,null,2,3]
// Output: [1,2,3]
tree1 := &TreeNode {
1,
nil,
&TreeNode {
2,
&TreeNode{3, nil, nil},
nil,
},
}
fmt.Println(preorderTraversal(tree1)) // [1,2,3]
// Example 2:
// Input: root = []
// Output: []
fmt.Println(preorderTraversal(nil)) // []
// Example 3:
// Input: root = [1]
// Output: [1]
tree3 := &TreeNode {
1,
nil,
nil,
}
fmt.Println(preorderTraversal(tree3)) // [1]
}