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129 lines (112 loc) · 1.86 KB
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2018-7-16 algorithm calculation.c
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129 lines (112 loc) · 1.86 KB
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#include<stdio.h>
#include<stdlib.h>
#define MAXOP 100
#define NUMBER '0'
int getop(char[]);
void push(double);
double pop(void);
//这一段程序的功能是,根据首字母的类型,保留数字压入栈中,除去其他类型的字符
int main()
{
int type;
double op2;
char s[MAXOP];
while ((type = getop(s)) != EOF)
{
switch (type)
{
case NUMBER:
push(atof(s));
break;
case'+':
push(pop() + pop());
break;
case'*':
push(pop()*pop());
break;
case'-':
op2 = pop();
push(pop() - op2);
break;
case'/':
op2 = pop();
if (op2 != 0.0)
{
push(pop() / op2);
}
else
{
printf("error:zero divisor\n");
break;
}
case'\n':
printf("\t%.8g\n", pop());
break;
default:
printf("error");
break;
}
}
return 0;
}
#define MAXVAL 100
int sp = 0;
double val[MAXVAL];
//push函数,把f压入值栈
void push(double f)
{
if (sp < MAXVAL)
val[sp++] = f;//后++
else
printf("error:stack full");
}
//pop函数:弹出并返回栈顶的值
double pop(void)
{
if (sp > 0)
return val[--sp];//先--
else
{
printf("error:stack empty\n");
return 0.0;
}
}
#include <ctype.h>
int getch(void);
void ungetch(int);
//getop:获取下一个运算符或数值操作数
int getop(char s[])
{
int i, c;
while ((s[0] = c = getch()) == ' ' || c == '\t')
;
s[1] = '\0';
if (!isdigit(c) && c != '.')
return c;
i = 0;
if (isdigit(c))
while (isdigit(s[++i] = c = getch()))
;
if (c == '.')
while (isdigit(s[++i] = c = getch()))
;
s[i] = '\0';
if (c != EOF)
ungetch(c);
return NUMBER;
}
#define BUFSIZE 100
char buf[BUFSIZE];
int bufp = 0;
int getch(void)
{
return(bufp > 0) ? buf[--bufp] : getchar();
}
void ungetch(int c)
{
if (bufp >= BUFSIZE)
printf("ungetch");
else
buf[bufp++] = c;
}
//有些时候重新编译链接的时候出错需要把原debug里的exe删除重新生成