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401.binary-watch.cpp
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89 lines (85 loc) · 2.03 KB
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/*
* @lc app=leetcode id=401 lang=cpp
*
* [401] Binary Watch
*
* https://leetcode.com/problems/binary-watch/description/
*
* algorithms
* Easy (50.79%)
* Likes: 993
* Dislikes: 1856
* Total Accepted: 112K
* Total Submissions: 220.3K
* Testcase Example: '1'
*
* A binary watch has 4 LEDs on the top to represent the hours (0-11), and 6
* LEDs on the bottom to represent the minutes (0-59). Each LED represents a
* zero or one, with the least significant bit on the right.
*
*
* For example, the below binary watch reads "4:51".
*
*
*
*
* Given an integer turnedOn which represents the number of LEDs that are
* currently on (ignoring the PM), return all possible times the watch could
* represent. You may return the answer in any order.
*
* The hour must not contain a leading zero.
*
*
* For example, "01:00" is not valid. It should be "1:00".
*
*
* The minute must be consist of two digits and may contain a leading
* zero.
*
*
* For example, "10:2" is not valid. It should be "10:02".
*
*
*
* Example 1:
* Input: turnedOn = 1
* Output:
* ["0:01","0:02","0:04","0:08","0:16","0:32","1:00","2:00","4:00","8:00"]
* Example 2:
* Input: turnedOn = 9
* Output: []
*
*
* Constraints:
*
*
* 0 <= turnedOn <= 10
*
*
*/
// @lc code=start
class Solution {
public:
vector<string> readBinaryWatch(int turnedOn) {
vector<int> hours = {1, 2, 4, 8}, minutes = {1, 2, 4, 8, 16, 32};
vector<string> ans;
string s;
for(int hour = 0;hour<12;hour++){
for(int min =0;min<60;min++){
s ="";
if(__builtin_popcount(hour) + __builtin_popcount(min) == turnedOn )
{
s += to_string(hour) + ":";
if(min < 10)
{
s += "0";
}
s += to_string(min);
ans.push_back(s);
}
}
}
return ans;
}
};
// @lc code=end