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35.search-insert-position.cpp
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79 lines (75 loc) · 1.43 KB
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/*
* @lc app=leetcode id=35 lang=cpp
*
* [35] Search Insert Position
*
* https://leetcode.com/problems/search-insert-position/description/
*
* algorithms
* Easy (42.27%)
* Likes: 9387
* Dislikes: 461
* Total Accepted: 1.7M
* Total Submissions: 4M
* Testcase Example: '[1,3,5,6]\n5'
*
* Given a sorted array of distinct integers and a target value, return the
* index if the target is found. If not, return the index where it would be if
* it were inserted in order.
*
* You must write an algorithm with O(log n) runtime complexity.
*
*
* Example 1:
*
*
* Input: nums = [1,3,5,6], target = 5
* Output: 2
*
*
* Example 2:
*
*
* Input: nums = [1,3,5,6], target = 2
* Output: 1
*
*
* Example 3:
*
*
* Input: nums = [1,3,5,6], target = 7
* Output: 4
*
*
*
* Constraints:
*
*
* 1 <= nums.length <= 10^4
* -10^4 <= nums[i] <= 10^4
* nums contains distinct values sorted in ascending order.
* -10^4 <= target <= 10^4
*
*
*/
// @lc code=start
class Solution
{
public:
int searchInsert(vector<int> &nums, int target)
{
if ( nums.size() == 0)
return 0;
int n = nums.size();
int l = 0, r = n - 1;
while (l < r)
{
int m = l + (r - l) / 2;
if (nums[m] == target) return m;
else if (nums[m] > target) r = m;
else l = m + 1;
}
return nums[l] < target ? l + 1 : l;
}
};
// @lc code=end