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303.range-sum-query-immutable.cpp
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87 lines (83 loc) · 1.97 KB
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/*
* @lc app=leetcode id=303 lang=cpp
*
* [303] Range Sum Query - Immutable
*
* https://leetcode.com/problems/range-sum-query-immutable/description/
*
* algorithms
* Easy (56.25%)
* Likes: 2284
* Dislikes: 1700
* Total Accepted: 384.7K
* Total Submissions: 670.3K
* Testcase Example: '["NumArray","sumRange","sumRange","sumRange"]\n' +
'[[[-2,0,3,-5,2,-1]],[0,2],[2,5],[0,5]]'
*
* Given an integer array nums, handle multiple queries of the following
* type:
*
*
* Calculate the sum of the elements of nums between indices left and right
* inclusive where left <= right.
*
*
* Implement the NumArray class:
*
*
* NumArray(int[] nums) Initializes the object with the integer array nums.
* int sumRange(int left, int right) Returns the sum of the elements of nums
* between indices left and right inclusive (i.e. nums[left] + nums[left + 1] +
* ... + nums[right]).
*
*
*
* Example 1:
*
*
* Input
* ["NumArray", "sumRange", "sumRange", "sumRange"]
* [[[-2, 0, 3, -5, 2, -1]], [0, 2], [2, 5], [0, 5]]
* Output
* [null, 1, -1, -3]
*
* Explanation
* NumArray numArray = new NumArray([-2, 0, 3, -5, 2, -1]);
* numArray.sumRange(0, 2); // return (-2) + 0 + 3 = 1
* numArray.sumRange(2, 5); // return 3 + (-5) + 2 + (-1) = -1
* numArray.sumRange(0, 5); // return (-2) + 0 + 3 + (-5) + 2 + (-1) = -3
*
*
*
* Constraints:
*
*
* 1 <= nums.length <= 10^4
* -10^5 <= nums[i] <= 10^5
* 0 <= left <= right < nums.length
* At most 10^4 calls will be made to sumRange.
*
*
*/
// @lc code=start
class NumArray {
private:
vector <int> num;
public:
NumArray(vector<int>& nums) {
num = nums;
}
int sumRange(int left, int right) {
int sum = 0;
for(int i = left;i<=right;i++){
sum += num[i];
}
return sum;
}
};
/**
* Your NumArray object will be instantiated and called as such:
* NumArray* obj = new NumArray(nums);
* int param_1 = obj->sumRange(left,right);
*/
// @lc code=end