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20-validparenthesis.py
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67 lines (47 loc) · 1.53 KB
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# %%
"""
Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
An input string is valid if:
Open brackets must be closed by the same type of brackets.
Open brackets must be closed in the correct order.
Example 1:
Input: s = "()"
Output: true
Example 2:
Input: s = "()[]{}"
Output: true
Example 3:
Input: s = "(]"
Output: false
Constraints:
1 <= s.length <= 104
s consists of parentheses only '()[]{}'."""
#%%
class Solution:
def isValid(self, s: str) -> bool:
rounddict,curlydict,squaredict = 0,0,0
currentopens = []
opens = ['[','{','(']
closes = [']','}',')']
for c in s:
if c in opens:
currentopens.append(c)
if c =='[' : squaredict += 1
if c == '{' : curlydict += 1
if c == '(': rounddict +=1
if c in closes:
if len(currentopens) == 0: return False
pop = currentopens.pop(-1)
if c == ']':
if pop != '[': return False
squaredict -= 1
if c == '}':
if pop != '{': return False
curlydict -= 1
if c == ')':
if pop != '(': return False
rounddict -= 1
if (rounddict != 0) or (squaredict != 0) or (curlydict != 0):
return False
return True
# %%