measures_as_strings: how to split chords in the same measure?

[enridaga]

Hi! Thanks for this nice piece of work :)

I love the ability to extract a flattened sequence of chords. However, the measures_as_strings returns chords in the same measures attached together as single string without separation. Is this intended? How to distinguish them and (eventually) know the relative duration?

For example,

print(my_tune.measures_as_strings)

*['D-', 'Eh7A7b9', 'G-7C7', 'F^7', 'Eh7A7b9', 'D-', 'Eh7', 'A7b9', 'D-7', 'D-6', 'D-7', 'D-6', 'D-', 'Eh7A7b9', 'G-7C7', 'F^7', 'Eh7A7b9', 'D-', 'Eh7', 'A7b9', 'D-7', 'D-6', 'D-7', 'D-6', 'F^7', 'G-7C7', 'F^7', 'Eh7A7b9', 'D-', 'Eh7A7b9', 'G-7C7', 'F^7', 'Eh7A7b9', 'D-', 'C7sus', 'C7sus', 'C7sus', 'C7sus', 'C7sus', 'C7sus', 'C7susA7b9', 'D-', 'D-']

I would like to know that in measure 2 there are 2 chords each one occupying half of the measure 'Eh7A7b9' => 'Eh7 A7b9'. I wonder how to treat the case where you have three chords, e.g. C (repeat) F G`, where the first chord occupies 2 bits.

[rtwfroody]

This is what I did:

        chords = []
        for bar in tune.measures_as_strings:
            chords += re.findall(r"[A-G][^A-G/]*(?:/[A-G][^A-G]*)?", bar)

That doesn't address how long each chord takes. I just wanted a list of all of them.