增加text/json和text/xml响应类型的支持

Author: xljiulang

WebApiClientCore/Attributes/ReturnAttributes/JsonReturnAttribute.cs

@@ -1,4 +1,5 @@
-using System.Net.Http.Headers;
+using System;
+using System.Net.Http.Headers;
 using System.Threading.Tasks;
 using WebApiClientCore.HttpContents;
 
@@ -26,6 +27,23 @@ public JsonReturnAttribute(double acceptQuality)
         {
         }
 
+        /// <summary>
+        /// 指示响应的ContentType与AcceptContentType是否匹配
+        /// 返回false则调用下一个ApiReturnAttribute来处理响应结果
+        /// </summary>
+        /// <param name="responseContentType">响应的ContentType</param>
+        /// <returns></returns>
+        protected override bool IsMatchAcceptContentType(MediaTypeHeaderValue? responseContentType)
+        {
+            var result = base.IsMatchAcceptContentType(responseContentType);
+            if (result == false)
+            {
+                var mediaType = responseContentType?.MediaType;
+                result = string.Equals(mediaType, "text/json", StringComparison.OrdinalIgnoreCase);
+            }
+            return result;
+        }
+
         /// <summary>
         /// 设置强类型模型结果值
         /// </summary>

WebApiClientCore/Attributes/ReturnAttributes/XmlReturnAttribute.cs

@@ -1,4 +1,5 @@
-using System.Net.Http.Headers;
+using System;
+using System.Net.Http.Headers;
 using System.Threading.Tasks;
 using WebApiClientCore.HttpContents;
 
@@ -26,6 +27,23 @@ public XmlReturnAttribute(double acceptQuality)
         {
         }
 
+        /// <summary>
+        /// 指示响应的ContentType与AcceptContentType是否匹配
+        /// 返回false则调用下一个ApiReturnAttribute来处理响应结果
+        /// </summary>
+        /// <param name="responseContentType">响应的ContentType</param>
+        /// <returns></returns>
+        protected override bool IsMatchAcceptContentType(MediaTypeHeaderValue? responseContentType)
+        {
+            var result = base.IsMatchAcceptContentType(responseContentType);
+            if (result == false)
+            {
+                var mediaType = responseContentType?.MediaType;
+                result = string.Equals(mediaType, "text/xml", StringComparison.OrdinalIgnoreCase);
+            }
+            return result;
+        }
+
         /// <summary>
         /// 设置强类型模型结果值
         /// </summary>