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offer-03-02-DuplicationInArrayNoEdit.c
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104 lines (91 loc) · 1.64 KB
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#include <stdio.h>
#include <stdlib.h>
#include "minunit.h"
int countRange(int *nums, int numsSize, int begin, int end);
// question similar offer-03-01, don't modify input array
int getDuplication(int *nums, int numsSize)
{
if (nums == NULL || numsSize == 0)
{
return -1;
}
int *hash = (int *)malloc(sizeof(int) * numsSize);
for (int i = 0; i < numsSize; i++)
{
if (hash[nums[i]] == 1)
{
return nums[i];
}
else
{
hash[nums[i]] = 1;
}
}
return -1;
}
// binary search
int getDuplication1(int *nums, int numsSize)
{
if (nums == NULL || numsSize == 0)
{
return -1;
}
int begin = 1, end = numsSize - 1;
while (begin <= end)
{
int mid = begin + (end - begin) / 2;
int count = countRange(nums, numsSize, begin, mid);
if (end == begin)
{
if (count > 1)
{
return begin;
}
else
{
break;
}
}
if (count > (mid - begin + 1))
{
end = mid;
}
else
{
begin = mid + 1;
}
}
return -1;
}
int countRange(int *nums, int numsSize, int begin, int end)
{
if (nums == NULL || numsSize == 0)
{
return 0;
}
int count = 0;
for (int i = 0; i < numsSize; i++)
{
if (nums[i] >= begin && nums[i] <= end)
{
count++;
}
}
return count;
}
MU_TEST(test_case)
{
int a[] = {2, 3, 5, 4, 3, 2, 6, 7};
mu_assert_int_eq(3, getDuplication(a, (int)sizeof(a) / sizeof(a[0])));
mu_assert_int_eq(3, getDuplication1(a, (int)sizeof(a) / sizeof(a[0])));
}
MU_TEST_SUITE(test_suite)
{
MU_RUN_TEST(test_case);
}
int main()
{
MU_RUN_SUITE(test_suite);
MU_REPORT();
return MU_EXIT_CODE;
}