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39.combination-sum.go
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97 lines (92 loc) · 1.88 KB
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/*
* @lc app=leetcode id=39 lang=golang
*
* [39] Combination Sum
*
* https://leetcode.com/problems/combination-sum/description/
*
* algorithms
* Medium (55.22%)
* Likes: 3974
* Dislikes: 119
* Total Accepted: 552.3K
* Total Submissions: 986.9K
* Testcase Example: '[2,3,6,7]\n7'
*
* Given a set of candidate numbers (candidates) (without duplicates) and a
* target number (target), find all unique combinations in candidates where the
* candidate numbers sums to target.
*
* The same repeated number may be chosen from candidates unlimited number of
* times.
*
* Note:
*
*
* All numbers (including target) will be positive integers.
* The solution set must not contain duplicate combinations.
*
*
* Example 1:
*
*
* Input: candidates = [2,3,6,7], target = 7,
* A solution set is:
* [
* [7],
* [2,2,3]
* ]
*
*
* Example 2:
*
*
* Input: candidates = [2,3,5], target = 8,
* A solution set is:
* [
* [2,2,2,2],
* [2,3,3],
* [3,5]
* ]
*
*
*
* Constraints:
*
*
* 1 <= candidates.length <= 30
* 1 <= candidates[i] <= 200
* Each element of candidate is unique.
* 1 <= target <= 500
*
*
*/
// @lc code=start
func combinationSum(candidates []int, target int) [][]int {
return combinationSum1(candidates, target)
}
func combinationSum1(candidates []int, target int) [][]int {
output, track := [][]int{}, []int{}
backtrack(&output, candidates, track, target, 0)
return output
}
func backtrack(output *[][]int, candidates, track []int, target, start int) {
if target == 0 {
path := make([]int, len(track))
copy(path, track)
*output = append(*output, path)
return
}
if target < 0 {
return
}
for i := start; i < len(candidates); i++ {
remain := target - candidates[i]
if remain >= 0 {
track = append(track, candidates[i])
backtrack(output, candidates, track, remain, i)
track = track[:len(track)-1]
}
}
}
// @lc code=end