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13.roman-to-integer.go
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131 lines (125 loc) · 2.65 KB
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/*
* @lc app=leetcode id=13 lang=golang
*
* [13] Roman to Integer
*
* https://leetcode.com/problems/roman-to-integer/description/
*
* algorithms
* Easy (55.37%)
* Likes: 2325
* Dislikes: 3578
* Total Accepted: 724.6K
* Total Submissions: 1.3M
* Testcase Example: '"III"'
*
* Roman numerals are represented by seven different symbols: I, V, X, L, C, D
* and M.
*
*
* Symbol Value
* I 1
* V 5
* X 10
* L 50
* C 100
* D 500
* M 1000
*
* For example, two is written as II in Roman numeral, just two one's added
* together. Twelve is written as, XII, which is simply X + II. The number
* twenty seven is written as XXVII, which is XX + V + II.
*
* Roman numerals are usually written largest to smallest from left to right.
* However, the numeral for four is not IIII. Instead, the number four is
* written as IV. Because the one is before the five we subtract it making
* four. The same principle applies to the number nine, which is written as IX.
* There are six instances where subtraction is used:
*
*
* I can be placed before V (5) and X (10) to make 4 and 9.
* X can be placed before L (50) and C (100) to make 40 and 90.
* C can be placed before D (500) and M (1000) to make 400 and 900.
*
*
* Given a roman numeral, convert it to an integer. Input is guaranteed to be
* within the range from 1 to 3999.
*
* Example 1:
*
*
* Input: "III"
* Output: 3
*
* Example 2:
*
*
* Input: "IV"
* Output: 4
*
* Example 3:
*
*
* Input: "IX"
* Output: 9
*
* Example 4:
*
*
* Input: "LVIII"
* Output: 58
* Explanation: L = 50, V= 5, III = 3.
*
*
* Example 5:
*
*
* Input: "MCMXCIV"
* Output: 1994
* Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
*
*/
// @lc code=start
func romanToInt(s string) int {
return romanToInt2(s)
}
// cmp s[i] < s[i+1]
func romanToInt2(s string) int {
if len(s) == 0 {
return 0
}
hash := map[byte]int{'I': 1, 'V': 5, 'X': 10, 'L': 50, 'C': 100, 'D': 500, 'M': 1000}
retVal := 0
for i := 0; i < len(s); i++ {
if i != len(s)-1 && hash[s[i]] < hash[s[i+1]] {
retVal -= hash[s[i]]
} else {
retVal += hash[s[i]]
}
}
return retVal
}
func romanToInt1(s string) int {
if len(s) == 0 {
return 0
}
hash := map[byte]int{'I': 1, 'V': 5, 'X': 10, 'L': 50, 'C': 100, 'D': 500, 'M': 1000}
retVal := 0
for i := 0; i < len(s); {
if i == len(s)-1 {
retVal += hash[s[i]]
i++
} else {
// forward next 2
if hash[s[i]] < hash[s[i+1]] {
retVal += hash[s[i+1]] - hash[s[i]]
i = i + 2
} else {
retVal += hash[s[i]]
i++
}
}
}
return retVal
}
// @lc code=end