https://leetcode.com/problems/longest-continuous-increasing-subsequence/
Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).
Example 1:
Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1. + 7 = 9,
return [0, 1].
- Iterate through array and compare.
- Update count and compare max.
- Count
- Language: Java
class Solution {
public int findLengthOfLCIS(int[] nums) {
int res=0, count=0;
for(int i=0;i<nums.length;i++){
if(i==0 || nums[i]>nums[i-1]) res=Math.max(res, ++count);
else count=1;
}
return res;
}
}Complexity
- Time Complexity:O(N)
- Space Complexity:O(1)