Add operations_on_set.py

Author: amratadev

operations_on_set.py

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+set1 = {'Ram', 'Shyam', 'Jenny'}
+set2 = {'Jenny', 'Jiya', 'Aakash'}
+set3 = {'Ankur', 'Pradeep'}
+
+print(set1.union(set2, set3))  
+# ✅ union() → combines all sets, removes duplicates
+# Output: {'Ram','Shyam','Jenny','Jiya','Aakash','Ankur','Pradeep'}
+
+print(set1 | set2 | set3)  
+# ✅ Same as union, but using | operator (all operands must be sets)
+
+print(set1.union(('Mohan','Jenny')))  
+# ✅ union() can work with other iterables (like tuple/list), duplicates ignored
+
+set1.update(set2)
+print(set1)  
+# ✅ update() → adds all elements of set2 into set1
+
+set1.update(['Jenny','Mohan'])
+print(set1)  
+# ✅ update() → can add elements from list/tuple also
+
+set1 |= set2
+print(set1)  
+# ✅ |= operator works same as update()
+
+print(set1.intersection(set2, set3))  
+# ✅ intersection() → common elements among all sets
+# Here no common element → Output: set()
+
+print(set1 & set2)  
+# ✅ & operator → intersection of two sets
+# Output: {'Jenny'}
+
+print(set1.intersection(['Mohan','Shiva']))  
+# ✅ intersection() works with other iterables too
+# Output: {'Mohan'} if present in set1
+
+print(set1 & set2 & set3)  
+# ✅ intersection of all three sets
+# Output: set() (no common element)
+
+set2.intersection_update(set1)
+print(set2)  
+print(set1)  
+# ✅ intersection_update() → modifies set2, keeps only common elements with set1
+# set2 becomes {'Jenny'}
+
+set2.intersection_update(['Mohan','Shiva'])
+print(set2)  
+# ✅ intersection_update() with iterable → keeps only common elements
+# 'Jenny' not in ['Mohan','Shiva'] → set2 becomes empty set()