-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy path6-7.tex
More file actions
267 lines (208 loc) · 9.31 KB
/
6-7.tex
File metadata and controls
267 lines (208 loc) · 9.31 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
\documentclass[a4paper]{report}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{textcomp}
\usepackage{amsmath, amssymb}
\usepackage{xcolor}
\usepackage{tcolorbox}
\tcbuselibrary{theorems}
% Definitions & Theorems
\newtcbtheorem
[]% init options
{definition}% name
{Definition}% title
{%
colback=green!5,
colframe=green!35!black,
fonttitle=\bfseries,
}% options
{def}% prefix
\newtcbtheorem
[]% init options
{theorem}% name
{Theorem}% title
{%
colback=red!5,
colframe=red!35!black,
fonttitle=\bfseries,
}% options
{thrm}% prefix
\newtcbtheorem
[]% init options
{example}% name
{Example}% title
{%
colback=blue!5,
colframe=blue!35!black,
fonttitle=\bfseries,
}% options
{expl}% prefix
% figure support
\usepackage{graphicx}
\graphicspath{ {./images/} }
\usepackage{import}
\usepackage{xifthen}
\pdfminorversion=7
\usepackage{pdfpages}
\usepackage{transparent}
\newcommand{\incfig}[1]{%
\def\svgwidth{\columnwidth}
\import{./figures/}{#1.pdf_tex}
}
\DeclareMathSymbol{\lsim}{\mathord}{symbols}{"18}
\usepackage{hyperref}
\hypersetup{
colorlinks,
citecolor=black,
filecolor=black,
linkcolor=black,
urlcolor=black
}
\begin{document}
\chapter{Set Theory}
All mathematical objects can be defined in terms of sets, and the language of set theory is used
in every mathematical subject.
\section{Definitions and the Element Method of Proof}
Sets, as defined earlier, are collections of objects, called elements. Using our new knowledge, we can
redefine some definitions.
\subsection{Subsets}
We can redefine some definitions of subsets: \[
A \subseteq B \Leftrightarrow \forall x, x \in A \to x \in B
.\]
\[
A \not\subseteq B \Leftrightarrow \exists x \mid x \in A \land x \not\in B
.\]
Recall that a \textbf{proper subset} is a subset that is not equal to its containing set.
We can prove for two sets $X$ and $Y$ that $X \subseteq Y$ by \textbf{supposing} that $x$ is a particular but
arbitrarily chosen element of $X$, and \textbf{showing} that $x$ is also an element of $Y$.
\begin{definition}{Set Equality}{label}
Set $A$ equals set $B$ if, and only if, $A \subseteq B$ and $B \subseteq A$.
\end{definition}
\subsection{Operations on Sets}
\begin{definition}{Operations}{label}
Let $A$ and $B$ be subsets of a universal set $U$.
\begin{enumerate}
\item The \textbf{union} of $A$ and $B$, denoted $A \cup B$, is the set of all elements
that are in at least one of $A$ or $B$.
\item The \textbf{intersection} of $A$ and $B$, denoted $A \cap B$, is the set
of all elements that are common to both $A$ and $B$.
\item The \textbf{difference} of $B$ minus $A$ (or \textbf{relative complement}
of $A$ in $B$), denoted $B - A$, is the set of all elements that are in
$B$ and not $A$.
\item The \textbf{complement} of $A$, denoted $A^c$, is the set of all elements
in $U$ that are not in $A$.
\end{enumerate}
\end{definition}
\includegraphics[scale=0.65]{setops}
\subsection{Disjoint Sets and Partitions}
A group of sets are \textbf{mutually disjoint} if the intersection of all pairs of sets is equal to
the empty set $\emptyset$.
\begin{definition}{Partition}{label}
A finite or infinite collection of nonempty sets $\{A_1, A_2, A_3 \ldots\}$ is a \textbf{partition}
of a set $A$ if, and only if,
\begin{enumerate}
\item $A$ is the union of all the $A_i$
\item The sets $A_1,A_2,A_3 \ldots$ are mutually disjoint.
\end{enumerate}
\end{definition}
\begin{definition}{Power Sets}{label}
Given a set $A$, the \textbf{power set} of $A$, denoted $\wp(A)$, is the set of all subsets of $A$.
\end{definition}
\begin{definition}{Cartesian Product}{label}
In general, \[
A_1 \times A_2 \times \ldots A_n = \{(a_1, a_2, \ldots , a_n) \mid a_1 \in A_1, a_2 \in A_2, \ldots , a_n \in A_n \}
.\]
Note that $A_1 \times A_2 \times A_3$ is not quite the same thing as $(A_1 \times A_2) \times A_3$
because of tuple ordering.
\end{definition}
\section{Properties of Sets}
\begin{theorem}{Some Subset Relations}{label}
\begin{enumerate}
\item Inclusion of Intersection: $A \cap B \subseteq A$ and vice versa
\item Inclusion in Union: $A \subseteq A \cup B$ and vice versa
\item Transitive Property of Subsets: $A \subseteq B \land B \subseteq C \to A \subseteq C$
\end{enumerate}
To prove these theorems, \emph{suppose} that there is some arbitrary element of $A$ and show
that it is also in $B$.
\end{theorem}
\includegraphics[scale=0.65]{setids}
In general, to prove set equality, you prove that set $A$ is a subset of set $B$, and that
set $B$ is a subset of set $A$. Additionally, to prove that a set $X$ is equal to the empty set
$\emptyset$, suppose $X$ has an element and derive a contradiction.
Additionally, casework is helpful when dealing with unions. It may be helpful to split a union into
2 cases.
\chapter{Functions}
In this chapter we go more in depth into properties of functions and their composition.
\section{Functions Defined on General Sets}
\begin{definition}{Function}{label}
A \textbf{function} from a set $X$ to a set $Y$, denoted $f: X \to Y$, is a relation from
$X$, the \textbf{domain}, to $Y$, the \textbf{co-domain}, that satisfies two properties:
\begin{enumerate}
\item Every element in $X$ is related to some element in $Y$
\item No element in $X$ is related to more than one element in $Y$.
\end{enumerate}
The set of all values of $f$ is called the \emph{range of f} or the \emph{image of X under f}.
If there exists some $x$ such that $f(x)=y$, then x is called a \textbf{preimage
(or inverse image) of $y$}.
Two functions $F: X \to Y$ and $G: X \to Y$ are considered equal if, for all $x \in X, F(x) = G(x)$
\end{definition}
\begin{definition}{Identity Function}{label}
The identity function $I_X$ is a function from $X \to X$ by which $I_X(x) = x \forall x \in X$.
\end{definition}
\begin{definition}{Logarithmic Function}{label}
The log function $\log_b{x}=y$ (from $\mathbb{R}^{+}$ to $\mathbb{R}$) maps a number to the $y$ in the solution of
the equation $b^y=x$.
\end{definition}
\subsection{Well Defined Functions}
We say that a function is \textbf{not well defined} if it fails to satisfy at least one of the
requirements for being a function. A function being well defined really means that it qualifies
to be called a function.
\section{One-to-One and Onto, Inverse Functions}
\subsection{One-to-one}
A function is \textbf{one-to-one} (or \textbf{injective}) if, and only if, every input has a unique
output. Symbolically, $\forall x_1, x_2 \in X, f(x_1)=f(x_2) \to x_1 = x_2$.
To prove that $f$ is one-to-one, you \textbf{suppose} $x_1$ and $x_2$ are elements of $X$ such that
$f(x_1)=f(x_2)$, and \textbf{show} that $x_1=x_2$.
\subsection{Onto}
A function is \textbf{onto} (or \textbf{surjective}) if, and only if, the co-domain of the function
is equal to its image. Symbolically, $\forall y \in Y, \exists x \in X \mid f(x) = y$.
To prove that $f$ is onto, you \textbf{suppose} $y$ is in $Y$, and \textbf{show} that
there exists an element in $x$ such that $y = f(x)$.
\subsection{One-to-one correspondences and Inverse Functions}
\begin{definition}{Bijection}{label}
A \textbf{one-to-one correspondence} (or \textbf{bijection}) from a set $X$ to a set $Y$ is
a function that is both one-to-one and onto.
\end{definition}
\begin{theorem}{Inverse Functions}{label}
Suppose $F: X \to Y$ is a one-to-one correspondence. Then there is a function $F^{-1}: Y \to X$
where $F^{-1}(y)=x$. Note that $F^{-1}$ is also a one-to-one correspondence.
Additionally, note that \[
f^{-1}(b) = a \Leftrightarrow f(a) = b
.\]
\end{theorem}
Finding an inverse function is done while proving that some function $F$ is onto.
\section{Composition of Functions}
The composition of functions (defined as $(g \circ f)(x) = g(f(x)) \forall x \in X$) for two
functions $f: X \to Y$ and $g: Y \to Z$ is $(g \circ f): X \to Z$.
Two compositions are equivalent if they have the same output for every input.
\subsection{Properties of Compositions}
\begin{theorem}{Composition of a Function with Its Inverse}{label}
$f^{-1} \circ f = I_X$ and $f \circ f^{-1} = I_Y$. This can be proved directly using the
definition of inverse.
\end{theorem}
\begin{theorem}{One-to-one/Onto Compositions}{label}
If $f: X \to Y$ and $g: Y \to Z$ are both one-to-one, then $g \circ f$ is one-to-one.
The same line of reasoning applies for onto functions.
\end{theorem}
\section{Cardinality and Sizes of Infinity}
\begin{definition}{Cardinality}{label}
Let $A$ and $B$ be any sets. \textbf{$A$ has the same cardinality as $B$} if, and only if, there is
a one-to-one correspondence from $A$ to $B$. Sets in terms of cardinality follow reflexive,
symmetric, and transitive properties.
\end{definition}
Note that if a set has the same cardinality as a set that is countably infinite, then the set is
also countably infinite. Surprisingly, the set of all rational numbers is countably infinite.
\subsection{Larger Infinities}
The set of all real numbers is uncountable. This can be proved using the Cantor diagonalization process.
Note that any subset of a countable set is countable, and any subset with an uncountable set is uncountable.
\end{document}