From 7966a1af40049919882b708a5745671473d918b9 Mon Sep 17 00:00:00 2001 From: Daniel Tinsley Date: Sat, 1 Nov 2025 19:53:45 -0500 Subject: [PATCH] Fix typo --- asymptotesAsLimits/digInVerticalAsymptotes.tex | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/asymptotesAsLimits/digInVerticalAsymptotes.tex b/asymptotesAsLimits/digInVerticalAsymptotes.tex index cc31a91..9e77322 100644 --- a/asymptotesAsLimits/digInVerticalAsymptotes.tex +++ b/asymptotesAsLimits/digInVerticalAsymptotes.tex @@ -167,7 +167,7 @@ %% \caption{A plot of $f(x)=\protect\frac{x^2-9x+14}{x^2-5+6}$.} %% \label{plot:(x^2-9x+14)/(x^2-5x+6)} \end{image} -Hence we have a vertical asymptote at $x=3$. Since $\displaystyle \lim_{x\to 2} f(x) = 5$ but $2$ is not in the domain of $f$, the graph of $f$ will have a hole a that point. We know there are no other vertical asymptotes because the function $f$ is continuous on $(-\infty, 2)$, $(2, 3)$, and $(3,\infty)$. +Hence we have a vertical asymptote at $x=3$. Since $\displaystyle \lim_{x\to 2} f(x) = 5$ but $2$ is not in the domain of $f$, the graph of $f$ will have a hole at that point. We know there are no other vertical asymptotes because the function $f$ is continuous on $(-\infty, 2)$, $(2, 3)$, and $(3,\infty)$. \end{explanation} \end{example}