diff --git a/asymptotesAsLimits/digInVerticalAsymptotes.tex b/asymptotesAsLimits/digInVerticalAsymptotes.tex
index cc31a91..9e77322 100644
--- a/asymptotesAsLimits/digInVerticalAsymptotes.tex
+++ b/asymptotesAsLimits/digInVerticalAsymptotes.tex
@@ -167,7 +167,7 @@
 %% \caption{A plot of $f(x)=\protect\frac{x^2-9x+14}{x^2-5+6}$.}
 %% \label{plot:(x^2-9x+14)/(x^2-5x+6)}
 \end{image}
-Hence we have a vertical asymptote at $x=3$. Since $\displaystyle \lim_{x\to 2} f(x) = 5$ but $2$ is not in the domain of $f$, the graph of $f$ will have a hole a that point. We know there are no other vertical asymptotes because the function $f$ is continuous on $(-\infty, 2)$, $(2, 3)$, and $(3,\infty)$.
+Hence we have a vertical asymptote at $x=3$. Since $\displaystyle \lim_{x\to 2} f(x) = 5$ but $2$ is not in the domain of $f$, the graph of $f$ will have a hole at that point. We know there are no other vertical asymptotes because the function $f$ is continuous on $(-\infty, 2)$, $(2, 3)$, and $(3,\infty)$.
 \end{explanation}
 \end{example}