2215.py

"""2215. Find the Difference of Two Arrays
    Given two 0-indexed integer arrays nums1 and nums2, return a list answer of size 2 where:
    answer[0] is a list of all distinct integers in nums1 which are not present in nums2.
    answer[1] is a list of all distinct integers in nums2 which are not present in nums1.
    Note that the integers in the lists may be returned in any order.
    

Example 1:
Input: nums1 = [1,2,3], nums2 = [2,4,6]
Output: [[1,3],[4,6]]

Explanation:For nums1, nums1[1] = 2 is present at index 0 of nums2, whereas nums1[0] = 1 and nums1[2] = 3 are not present in nums2. Therefore, answer[0] = [1,3].
For nums2, nums2[0] = 2 is present at index 1 of nums1, whereas nums2[1] = 4 and nums2[2] = 6 are not present in nums1. Therefore, answer[1] = [4,6].


Example 2:
Input: nums1 = [1,2,3,3], nums2 = [1,1,2,2]
Output: [[3],[]]

Explanation:For nums1, nums1[2] and nums1[3] are not present in nums2. Since nums1[2] == nums1[3], their value is only included once and answer[0] = [3].
Every integer in nums2 is present in nums1. Therefore, answer[1] = [].

 """



from typing import List

class Solution:
    def findDifference(self, nums1: List[int], nums2: List[int]) -> List[List[int]]:
        set1 = set(nums1)
        set2 = set(nums2)
        
        return [list(set1 - set2), list(set2 - set1)]


# test
if __name__ == "__main__":
    nums1 = [1, 2, 3]
    nums2 = [2, 4, 6]
    
    sol = Solution()
    result = sol.findDifference(nums1, nums2)
    
    print(result)